Input interpretation
![2-chloro-5-(trifluoromethyl)phenyl isocyanate | molar mass](../image_source/30eaad90c59118e31a3a68a53b5c1b7e.png)
2-chloro-5-(trifluoromethyl)phenyl isocyanate | molar mass
Result
![Find the molar mass, M, for 2-chloro-5-(trifluoromethyl)phenyl isocyanate: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: ClC_6H_3(CF_3)NCO Use the chemical formula to count the number of atoms, N_i, for each element: | N_i C (carbon) | 8 Cl (chlorine) | 1 F (fluorine) | 3 H (hydrogen) | 3 N (nitrogen) | 1 O (oxygen) | 1 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) C (carbon) | 8 | 12.011 Cl (chlorine) | 1 | 35.45 F (fluorine) | 3 | 18.998403163 H (hydrogen) | 3 | 1.008 N (nitrogen) | 1 | 14.007 O (oxygen) | 1 | 15.999 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) C (carbon) | 8 | 12.011 | 8 × 12.011 = 96.088 Cl (chlorine) | 1 | 35.45 | 1 × 35.45 = 35.45 F (fluorine) | 3 | 18.998403163 | 3 × 18.998403163 = 56.995209489 H (hydrogen) | 3 | 1.008 | 3 × 1.008 = 3.024 N (nitrogen) | 1 | 14.007 | 1 × 14.007 = 14.007 O (oxygen) | 1 | 15.999 | 1 × 15.999 = 15.999 M = 96.088 g/mol + 35.45 g/mol + 56.995209489 g/mol + 3.024 g/mol + 14.007 g/mol + 15.999 g/mol = 221.56 g/mol](../image_source/4c7d51528c086cc2534bbc373c9da9fe.png)
Find the molar mass, M, for 2-chloro-5-(trifluoromethyl)phenyl isocyanate: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: ClC_6H_3(CF_3)NCO Use the chemical formula to count the number of atoms, N_i, for each element: | N_i C (carbon) | 8 Cl (chlorine) | 1 F (fluorine) | 3 H (hydrogen) | 3 N (nitrogen) | 1 O (oxygen) | 1 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) C (carbon) | 8 | 12.011 Cl (chlorine) | 1 | 35.45 F (fluorine) | 3 | 18.998403163 H (hydrogen) | 3 | 1.008 N (nitrogen) | 1 | 14.007 O (oxygen) | 1 | 15.999 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) C (carbon) | 8 | 12.011 | 8 × 12.011 = 96.088 Cl (chlorine) | 1 | 35.45 | 1 × 35.45 = 35.45 F (fluorine) | 3 | 18.998403163 | 3 × 18.998403163 = 56.995209489 H (hydrogen) | 3 | 1.008 | 3 × 1.008 = 3.024 N (nitrogen) | 1 | 14.007 | 1 × 14.007 = 14.007 O (oxygen) | 1 | 15.999 | 1 × 15.999 = 15.999 M = 96.088 g/mol + 35.45 g/mol + 56.995209489 g/mol + 3.024 g/mol + 14.007 g/mol + 15.999 g/mol = 221.56 g/mol
Unit conversion
![0.22156 kg/mol (kilograms per mole)](../image_source/5988ace6855981b1a9c8f087b5ca6869.png)
0.22156 kg/mol (kilograms per mole)
Comparisons
![≈ 0.31 × molar mass of fullerene ( ≈ 721 g/mol )](../image_source/52e345b4e49fb637007bc1c8a4a35b0d.png)
≈ 0.31 × molar mass of fullerene ( ≈ 721 g/mol )
![≈ 1.1 × molar mass of caffeine ( ≈ 194 g/mol )](../image_source/f7b9e23c26facfd7abea6fcb23feba99.png)
≈ 1.1 × molar mass of caffeine ( ≈ 194 g/mol )
![≈ 3.8 × molar mass of sodium chloride ( ≈ 58 g/mol )](../image_source/603c78062caa006dbcf73d2fff093b53.png)
≈ 3.8 × molar mass of sodium chloride ( ≈ 58 g/mol )
Corresponding quantities
![Mass of a molecule m from m = M/N_A: | 3.7×10^-22 grams | 3.7×10^-25 kg (kilograms) | 222 u (unified atomic mass units) | 222 Da (daltons)](../image_source/b2806f38e0e99d94bafb15baf06ddebe.png)
Mass of a molecule m from m = M/N_A: | 3.7×10^-22 grams | 3.7×10^-25 kg (kilograms) | 222 u (unified atomic mass units) | 222 Da (daltons)
![Relative molecular mass M_r from M_r = M_u/M: | 222](../image_source/adba56b66302c2cd227d16dd08cef889.png)
Relative molecular mass M_r from M_r = M_u/M: | 222