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molar mass of disodium methanearsonate

Input interpretation

disodium methanearsonate | molar mass
disodium methanearsonate | molar mass

Result

Find the molar mass, M, for disodium methanearsonate: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: CH_3AsNa_2O_3 Use the chemical formula, CH_3AsNa_2O_3, to count the number of atoms, N_i, for each element:  | N_i  As (arsenic) | 1  C (carbon) | 1  H (hydrogen) | 3  Na (sodium) | 2  O (oxygen) | 3 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table:  | N_i | m_i/g·mol^(-1)  As (arsenic) | 1 | 74.921595  C (carbon) | 1 | 12.011  H (hydrogen) | 3 | 1.008  Na (sodium) | 2 | 22.98976928  O (oxygen) | 3 | 15.999 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: |   | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1)  As (arsenic) | 1 | 74.921595 | 1 × 74.921595 = 74.921595  C (carbon) | 1 | 12.011 | 1 × 12.011 = 12.011  H (hydrogen) | 3 | 1.008 | 3 × 1.008 = 3.024  Na (sodium) | 2 | 22.98976928 | 2 × 22.98976928 = 45.97953856  O (oxygen) | 3 | 15.999 | 3 × 15.999 = 47.997  M = 74.921595 g/mol + 12.011 g/mol + 3.024 g/mol + 45.97953856 g/mol + 47.997 g/mol = 183.933 g/mol
Find the molar mass, M, for disodium methanearsonate: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: CH_3AsNa_2O_3 Use the chemical formula, CH_3AsNa_2O_3, to count the number of atoms, N_i, for each element: | N_i As (arsenic) | 1 C (carbon) | 1 H (hydrogen) | 3 Na (sodium) | 2 O (oxygen) | 3 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) As (arsenic) | 1 | 74.921595 C (carbon) | 1 | 12.011 H (hydrogen) | 3 | 1.008 Na (sodium) | 2 | 22.98976928 O (oxygen) | 3 | 15.999 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) As (arsenic) | 1 | 74.921595 | 1 × 74.921595 = 74.921595 C (carbon) | 1 | 12.011 | 1 × 12.011 = 12.011 H (hydrogen) | 3 | 1.008 | 3 × 1.008 = 3.024 Na (sodium) | 2 | 22.98976928 | 2 × 22.98976928 = 45.97953856 O (oxygen) | 3 | 15.999 | 3 × 15.999 = 47.997 M = 74.921595 g/mol + 12.011 g/mol + 3.024 g/mol + 45.97953856 g/mol + 47.997 g/mol = 183.933 g/mol

Unit conversion

0.18393 kg/mol (kilograms per mole)
0.18393 kg/mol (kilograms per mole)

Comparisons

 ≈ 0.26 × molar mass of fullerene ( ≈ 721 g/mol )
≈ 0.26 × molar mass of fullerene ( ≈ 721 g/mol )
 ≈ 0.95 × molar mass of caffeine ( ≈ 194 g/mol )
≈ 0.95 × molar mass of caffeine ( ≈ 194 g/mol )
 ≈ 3.1 × molar mass of sodium chloride ( ≈ 58 g/mol )
≈ 3.1 × molar mass of sodium chloride ( ≈ 58 g/mol )

Corresponding quantities

Mass of a molecule m from m = M/N_A:  | 3.1×10^-22 grams  | 3.1×10^-25 kg (kilograms)  | 184 u (unified atomic mass units)  | 184 Da (daltons)
Mass of a molecule m from m = M/N_A: | 3.1×10^-22 grams | 3.1×10^-25 kg (kilograms) | 184 u (unified atomic mass units) | 184 Da (daltons)
Relative molecular mass M_r from M_r = M_u/M:  | 184
Relative molecular mass M_r from M_r = M_u/M: | 184