Input interpretation
cadmium niobate | molar mass
Result
Find the molar mass, M, for cadmium niobate: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: Cd_2Nb_2O_7 Use the chemical formula to count the number of atoms, N_i, for each element: | N_i Cd (cadmium) | 2 Nb (niobium) | 2 O (oxygen) | 7 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) Cd (cadmium) | 2 | 112.414 Nb (niobium) | 2 | 92.90637 O (oxygen) | 7 | 15.999 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) Cd (cadmium) | 2 | 112.414 | 2 × 112.414 = 224.828 Nb (niobium) | 2 | 92.90637 | 2 × 92.90637 = 185.81274 O (oxygen) | 7 | 15.999 | 7 × 15.999 = 111.993 M = 224.828 g/mol + 185.81274 g/mol + 111.993 g/mol = 522.634 g/mol
Unit conversion
0.52263 kg/mol (kilograms per mole)
Comparisons
≈ 0.73 × molar mass of fullerene ( ≈ 721 g/mol )
≈ 2.7 × molar mass of caffeine ( ≈ 194 g/mol )
≈ 8.9 × molar mass of sodium chloride ( ≈ 58 g/mol )
Corresponding quantities
Mass of a molecule m from m = M/N_A: | 8.7×10^-22 grams | 8.7×10^-25 kg (kilograms) | 523 u (unified atomic mass units) | 523 Da (daltons)
Relative molecular mass M_r from M_r = M_u/M: | 523