Input interpretation
3, 5-dichlorophenylzinc iodide | molar mass
Result
Find the molar mass, M, for 3, 5-dichlorophenylzinc iodide: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: Cl_2C_6H_3ZnI Use the chemical formula, Cl_2C_6H_3ZnI, to count the number of atoms, N_i, for each element: | N_i C (carbon) | 6 Cl (chlorine) | 2 H (hydrogen) | 3 I (iodine) | 1 Zn (zinc) | 1 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) C (carbon) | 6 | 12.011 Cl (chlorine) | 2 | 35.45 H (hydrogen) | 3 | 1.008 I (iodine) | 1 | 126.90447 Zn (zinc) | 1 | 65.38 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) C (carbon) | 6 | 12.011 | 6 × 12.011 = 72.066 Cl (chlorine) | 2 | 35.45 | 2 × 35.45 = 70.90 H (hydrogen) | 3 | 1.008 | 3 × 1.008 = 3.024 I (iodine) | 1 | 126.90447 | 1 × 126.90447 = 126.90447 Zn (zinc) | 1 | 65.38 | 1 × 65.38 = 65.38 M = 72.066 g/mol + 70.90 g/mol + 3.024 g/mol + 126.90447 g/mol + 65.38 g/mol = 338.27 g/mol
Unit conversion
0.3383 kg/mol (kilograms per mole)
Comparisons
≈ 0.47 × molar mass of fullerene ( ≈ 721 g/mol )
≈ 1.7 × molar mass of caffeine ( ≈ 194 g/mol )
≈ 5.8 × molar mass of sodium chloride ( ≈ 58 g/mol )
Corresponding quantities
Mass of a molecule m from m = M/N_A: | 5.6×10^-22 grams | 5.6×10^-25 kg (kilograms) | 338 u (unified atomic mass units) | 338 Da (daltons)
Relative molecular mass M_r from M_r = M_u/M: | 338