Input interpretation
![L-thiocitrulline | molar mass](../image_source/081adcb604d3b8b02a24ae12a76e3295.png)
L-thiocitrulline | molar mass
Result
![Find the molar mass, M, for L-thiocitrulline: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: C_6H_13N_3O_2S Use the chemical formula, C_6H_13N_3O_2S, to count the number of atoms, N_i, for each element: | N_i C (carbon) | 6 H (hydrogen) | 13 N (nitrogen) | 3 O (oxygen) | 2 S (sulfur) | 1 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) C (carbon) | 6 | 12.011 H (hydrogen) | 13 | 1.008 N (nitrogen) | 3 | 14.007 O (oxygen) | 2 | 15.999 S (sulfur) | 1 | 32.06 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) C (carbon) | 6 | 12.011 | 6 × 12.011 = 72.066 H (hydrogen) | 13 | 1.008 | 13 × 1.008 = 13.104 N (nitrogen) | 3 | 14.007 | 3 × 14.007 = 42.021 O (oxygen) | 2 | 15.999 | 2 × 15.999 = 31.998 S (sulfur) | 1 | 32.06 | 1 × 32.06 = 32.06 M = 72.066 g/mol + 13.104 g/mol + 42.021 g/mol + 31.998 g/mol + 32.06 g/mol = 191.25 g/mol](../image_source/65e77ea4fb2a5cf1011eae6a1bf99afa.png)
Find the molar mass, M, for L-thiocitrulline: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: C_6H_13N_3O_2S Use the chemical formula, C_6H_13N_3O_2S, to count the number of atoms, N_i, for each element: | N_i C (carbon) | 6 H (hydrogen) | 13 N (nitrogen) | 3 O (oxygen) | 2 S (sulfur) | 1 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) C (carbon) | 6 | 12.011 H (hydrogen) | 13 | 1.008 N (nitrogen) | 3 | 14.007 O (oxygen) | 2 | 15.999 S (sulfur) | 1 | 32.06 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) C (carbon) | 6 | 12.011 | 6 × 12.011 = 72.066 H (hydrogen) | 13 | 1.008 | 13 × 1.008 = 13.104 N (nitrogen) | 3 | 14.007 | 3 × 14.007 = 42.021 O (oxygen) | 2 | 15.999 | 2 × 15.999 = 31.998 S (sulfur) | 1 | 32.06 | 1 × 32.06 = 32.06 M = 72.066 g/mol + 13.104 g/mol + 42.021 g/mol + 31.998 g/mol + 32.06 g/mol = 191.25 g/mol
Unit conversion
![0.19125 kg/mol (kilograms per mole)](../image_source/8fe46c91e9f68a008fa4ded91bb66017.png)
0.19125 kg/mol (kilograms per mole)
Comparisons
![≈ 0.27 × molar mass of fullerene ( ≈ 721 g/mol )](../image_source/4e13eb534acdc5007cd6580ead83089d.png)
≈ 0.27 × molar mass of fullerene ( ≈ 721 g/mol )
![≈ 0.98 × molar mass of caffeine ( ≈ 194 g/mol )](../image_source/5297e4999ce4a0da51e95e209e5b0326.png)
≈ 0.98 × molar mass of caffeine ( ≈ 194 g/mol )
![≈ 3.3 × molar mass of sodium chloride ( ≈ 58 g/mol )](../image_source/6c32ca3c7c95ac90c9ed88f9a2d6cdf2.png)
≈ 3.3 × molar mass of sodium chloride ( ≈ 58 g/mol )
Corresponding quantities
![Mass of a molecule m from m = M/N_A: | 3.2×10^-22 grams | 3.2×10^-25 kg (kilograms) | 191 u (unified atomic mass units) | 191 Da (daltons)](../image_source/cb0eb472d31fda78adf307c6df867d02.png)
Mass of a molecule m from m = M/N_A: | 3.2×10^-22 grams | 3.2×10^-25 kg (kilograms) | 191 u (unified atomic mass units) | 191 Da (daltons)
![Relative molecular mass M_r from M_r = M_u/M: | 191](../image_source/67607742cc31c5f68194bd70e70490db.png)
Relative molecular mass M_r from M_r = M_u/M: | 191