Input interpretation
[5, 6]-fullerene-C70 | molar mass
Result
Find the molar mass, M, for [5, 6]-fullerene-C70: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: C_70 Use the chemical formula to count the number of atoms, N_i, for each element: | N_i C (carbon) | 70 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) C (carbon) | 70 | 12.011 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) C (carbon) | 70 | 12.011 | 70 × 12.011 = 840.770 M = 840.770 g/mol
Unit conversion
0.84077 kg/mol (kilograms per mole)
Comparisons
≈ 1.2 × molar mass of fullerene ( ≈ 721 g/mol )
≈ 4.3 × molar mass of caffeine ( ≈ 194 g/mol )
≈ 14 × molar mass of sodium chloride ( ≈ 58 g/mol )
Corresponding quantities
Mass of a molecule m from m = M/N_A: | 1.4×10^-21 grams | 1.4×10^-24 kg (kilograms) | 841 u (unified atomic mass units) | 841 Da (daltons)
Relative molecular mass M_r from M_r = M_u/M: | 841