Input interpretation
![nonafluorobutane sulfonate | molar mass](../image_source/e948177b85bc83e510d610b24262358b.png)
nonafluorobutane sulfonate | molar mass
Result
![Find the molar mass, M, for nonafluorobutane sulfonate: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: (C_4F_9O_3S)^- Use the chemical formula to count the number of atoms, N_i, for each element: | N_i F (fluorine) | 9 C (carbon) | 4 S (sulfur) | 1 O (oxygen) | 3 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) F (fluorine) | 9 | 18.998403163 C (carbon) | 4 | 12.011 S (sulfur) | 1 | 32.06 O (oxygen) | 3 | 15.999 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) F (fluorine) | 9 | 18.998403163 | 9 × 18.998403163 = 170.985628467 C (carbon) | 4 | 12.011 | 4 × 12.011 = 48.044 S (sulfur) | 1 | 32.06 | 1 × 32.06 = 32.06 O (oxygen) | 3 | 15.999 | 3 × 15.999 = 47.997 M = 170.985628467 g/mol + 48.044 g/mol + 32.06 g/mol + 47.997 g/mol = 299.09 g/mol](../image_source/dfb8ba626960a398d5de45f010db2243.png)
Find the molar mass, M, for nonafluorobutane sulfonate: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: (C_4F_9O_3S)^- Use the chemical formula to count the number of atoms, N_i, for each element: | N_i F (fluorine) | 9 C (carbon) | 4 S (sulfur) | 1 O (oxygen) | 3 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) F (fluorine) | 9 | 18.998403163 C (carbon) | 4 | 12.011 S (sulfur) | 1 | 32.06 O (oxygen) | 3 | 15.999 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) F (fluorine) | 9 | 18.998403163 | 9 × 18.998403163 = 170.985628467 C (carbon) | 4 | 12.011 | 4 × 12.011 = 48.044 S (sulfur) | 1 | 32.06 | 1 × 32.06 = 32.06 O (oxygen) | 3 | 15.999 | 3 × 15.999 = 47.997 M = 170.985628467 g/mol + 48.044 g/mol + 32.06 g/mol + 47.997 g/mol = 299.09 g/mol
Unit conversion
![0.2991 kg/mol (kilograms per mole)](../image_source/4fea59976d8f049d5694d0b017872bba.png)
0.2991 kg/mol (kilograms per mole)
Comparisons
![≈ 0.42 × molar mass of fullerene ( ≈ 721 g/mol )](../image_source/a3e7d83f92cba28638ec8836ab0f8687.png)
≈ 0.42 × molar mass of fullerene ( ≈ 721 g/mol )
![≈ 1.5 × molar mass of caffeine ( ≈ 194 g/mol )](../image_source/8ff1a3a3dd631b201132bd8084cd636e.png)
≈ 1.5 × molar mass of caffeine ( ≈ 194 g/mol )
![≈ 5.1 × molar mass of sodium chloride ( ≈ 58 g/mol )](../image_source/a2beca865739b18947eaf211006333bb.png)
≈ 5.1 × molar mass of sodium chloride ( ≈ 58 g/mol )
Corresponding quantities
![Mass of a molecule m from m = M/N_A: | 5×10^-22 grams | 5×10^-25 kg (kilograms) | 299 u (unified atomic mass units) | 299 Da (daltons)](../image_source/43d0f9c29439581b850ed59bb52cecbb.png)
Mass of a molecule m from m = M/N_A: | 5×10^-22 grams | 5×10^-25 kg (kilograms) | 299 u (unified atomic mass units) | 299 Da (daltons)
![Relative molecular mass M_r from M_r = M_u/M: | 299](../image_source/460548b67e75baf768deb84c492a4b7a.png)
Relative molecular mass M_r from M_r = M_u/M: | 299