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molar mass of cesium methanesulfonate

Input interpretation

cesium methanesulfonate | molar mass
cesium methanesulfonate | molar mass

Result

Find the molar mass, M, for cesium methanesulfonate: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: CH_3O_3SCs Use the chemical formula, CH_3O_3SCs, to count the number of atoms, N_i, for each element:  | N_i  C (carbon) | 1  Cs (cesium) | 1  H (hydrogen) | 3  O (oxygen) | 3  S (sulfur) | 1 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table:  | N_i | m_i/g·mol^(-1)  C (carbon) | 1 | 12.011  Cs (cesium) | 1 | 132.90545196  H (hydrogen) | 3 | 1.008  O (oxygen) | 3 | 15.999  S (sulfur) | 1 | 32.06 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: |   | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1)  C (carbon) | 1 | 12.011 | 1 × 12.011 = 12.011  Cs (cesium) | 1 | 132.90545196 | 1 × 132.90545196 = 132.90545196  H (hydrogen) | 3 | 1.008 | 3 × 1.008 = 3.024  O (oxygen) | 3 | 15.999 | 3 × 15.999 = 47.997  S (sulfur) | 1 | 32.06 | 1 × 32.06 = 32.06  M = 12.011 g/mol + 132.90545196 g/mol + 3.024 g/mol + 47.997 g/mol + 32.06 g/mol = 228.00 g/mol
Find the molar mass, M, for cesium methanesulfonate: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: CH_3O_3SCs Use the chemical formula, CH_3O_3SCs, to count the number of atoms, N_i, for each element: | N_i C (carbon) | 1 Cs (cesium) | 1 H (hydrogen) | 3 O (oxygen) | 3 S (sulfur) | 1 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) C (carbon) | 1 | 12.011 Cs (cesium) | 1 | 132.90545196 H (hydrogen) | 3 | 1.008 O (oxygen) | 3 | 15.999 S (sulfur) | 1 | 32.06 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) C (carbon) | 1 | 12.011 | 1 × 12.011 = 12.011 Cs (cesium) | 1 | 132.90545196 | 1 × 132.90545196 = 132.90545196 H (hydrogen) | 3 | 1.008 | 3 × 1.008 = 3.024 O (oxygen) | 3 | 15.999 | 3 × 15.999 = 47.997 S (sulfur) | 1 | 32.06 | 1 × 32.06 = 32.06 M = 12.011 g/mol + 132.90545196 g/mol + 3.024 g/mol + 47.997 g/mol + 32.06 g/mol = 228.00 g/mol

Unit conversion

0.228 kg/mol (kilograms per mole)
0.228 kg/mol (kilograms per mole)

Comparisons

 ≈ 0.32 × molar mass of fullerene ( ≈ 721 g/mol )
≈ 0.32 × molar mass of fullerene ( ≈ 721 g/mol )
 ≈ 1.2 × molar mass of caffeine ( ≈ 194 g/mol )
≈ 1.2 × molar mass of caffeine ( ≈ 194 g/mol )
 ≈ 3.9 × molar mass of sodium chloride ( ≈ 58 g/mol )
≈ 3.9 × molar mass of sodium chloride ( ≈ 58 g/mol )

Corresponding quantities

Mass of a molecule m from m = M/N_A:  | 3.8×10^-22 grams  | 3.8×10^-25 kg (kilograms)  | 228 u (unified atomic mass units)  | 228 Da (daltons)
Mass of a molecule m from m = M/N_A: | 3.8×10^-22 grams | 3.8×10^-25 kg (kilograms) | 228 u (unified atomic mass units) | 228 Da (daltons)
Relative molecular mass M_r from M_r = M_u/M:  | 228
Relative molecular mass M_r from M_r = M_u/M: | 228