Input interpretation
![bis(pentafluorophenyl)methanol | molar mass](../image_source/99822786c2b5a4a73846c74ef7cf1c6c.png)
bis(pentafluorophenyl)methanol | molar mass
Result
![Find the molar mass, M, for bis(pentafluorophenyl)methanol: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: (C_6F_5)_2CHOH Use the chemical formula, (C_6F_5)_2CHOH, to count the number of atoms, N_i, for each element: | N_i C (carbon) | 13 F (fluorine) | 10 H (hydrogen) | 2 O (oxygen) | 1 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) C (carbon) | 13 | 12.011 F (fluorine) | 10 | 18.998403163 H (hydrogen) | 2 | 1.008 O (oxygen) | 1 | 15.999 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) C (carbon) | 13 | 12.011 | 13 × 12.011 = 156.143 F (fluorine) | 10 | 18.998403163 | 10 × 18.998403163 = 189.984031630 H (hydrogen) | 2 | 1.008 | 2 × 1.008 = 2.016 O (oxygen) | 1 | 15.999 | 1 × 15.999 = 15.999 M = 156.143 g/mol + 189.984031630 g/mol + 2.016 g/mol + 15.999 g/mol = 364.142 g/mol](../image_source/f931f29c55b697e60051d80000db4ba9.png)
Find the molar mass, M, for bis(pentafluorophenyl)methanol: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: (C_6F_5)_2CHOH Use the chemical formula, (C_6F_5)_2CHOH, to count the number of atoms, N_i, for each element: | N_i C (carbon) | 13 F (fluorine) | 10 H (hydrogen) | 2 O (oxygen) | 1 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) C (carbon) | 13 | 12.011 F (fluorine) | 10 | 18.998403163 H (hydrogen) | 2 | 1.008 O (oxygen) | 1 | 15.999 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) C (carbon) | 13 | 12.011 | 13 × 12.011 = 156.143 F (fluorine) | 10 | 18.998403163 | 10 × 18.998403163 = 189.984031630 H (hydrogen) | 2 | 1.008 | 2 × 1.008 = 2.016 O (oxygen) | 1 | 15.999 | 1 × 15.999 = 15.999 M = 156.143 g/mol + 189.984031630 g/mol + 2.016 g/mol + 15.999 g/mol = 364.142 g/mol
Unit conversion
![0.36414 kg/mol (kilograms per mole)](../image_source/4baffd80648097baeac783b741de5fe4.png)
0.36414 kg/mol (kilograms per mole)
Comparisons
![≈ 0.51 × molar mass of fullerene ( ≈ 721 g/mol )](../image_source/42e9e195faaad58197e46cacb1d40160.png)
≈ 0.51 × molar mass of fullerene ( ≈ 721 g/mol )
![≈ 1.9 × molar mass of caffeine ( ≈ 194 g/mol )](../image_source/d2e969e35ef9f6b08f74e1ce89094739.png)
≈ 1.9 × molar mass of caffeine ( ≈ 194 g/mol )
![≈ 6.2 × molar mass of sodium chloride ( ≈ 58 g/mol )](../image_source/1f0dd8a49fae3ebdcbf4dca3e280bbd6.png)
≈ 6.2 × molar mass of sodium chloride ( ≈ 58 g/mol )
Corresponding quantities
![Mass of a molecule m from m = M/N_A: | 6×10^-22 grams | 6×10^-25 kg (kilograms) | 364 u (unified atomic mass units) | 364 Da (daltons)](../image_source/cfc352ecffadb34478430c4545d42b17.png)
Mass of a molecule m from m = M/N_A: | 6×10^-22 grams | 6×10^-25 kg (kilograms) | 364 u (unified atomic mass units) | 364 Da (daltons)
![Relative molecular mass M_r from M_r = M_u/M: | 364](../image_source/21900a66e2ef530bfd8a531ce3ce6f1b.png)
Relative molecular mass M_r from M_r = M_u/M: | 364