Input interpretation
![4, 4'-(hexafluoroisopropylidene)bis(benzoic acid) | molar mass](../image_source/acb8bb62af8155da0cb6c5c1782afbf9.png)
4, 4'-(hexafluoroisopropylidene)bis(benzoic acid) | molar mass
Result
![Find the molar mass, M, for 4, 4'-(hexafluoroisopropylidene)bis(benzoic acid): M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: C_17H_10F_6O_4 Use the chemical formula to count the number of atoms, N_i, for each element: | N_i F (fluorine) | 6 C (carbon) | 17 O (oxygen) | 4 H (hydrogen) | 10 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) F (fluorine) | 6 | 18.998403163 C (carbon) | 17 | 12.011 O (oxygen) | 4 | 15.999 H (hydrogen) | 10 | 1.008 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) F (fluorine) | 6 | 18.998403163 | 6 × 18.998403163 = 113.990418978 C (carbon) | 17 | 12.011 | 17 × 12.011 = 204.187 O (oxygen) | 4 | 15.999 | 4 × 15.999 = 63.996 H (hydrogen) | 10 | 1.008 | 10 × 1.008 = 10.080 M = 113.990418978 g/mol + 204.187 g/mol + 63.996 g/mol + 10.080 g/mol = 392.253 g/mol](../image_source/0e1c241c6b5ded34ae457fc1e60c0b91.png)
Find the molar mass, M, for 4, 4'-(hexafluoroisopropylidene)bis(benzoic acid): M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: C_17H_10F_6O_4 Use the chemical formula to count the number of atoms, N_i, for each element: | N_i F (fluorine) | 6 C (carbon) | 17 O (oxygen) | 4 H (hydrogen) | 10 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) F (fluorine) | 6 | 18.998403163 C (carbon) | 17 | 12.011 O (oxygen) | 4 | 15.999 H (hydrogen) | 10 | 1.008 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) F (fluorine) | 6 | 18.998403163 | 6 × 18.998403163 = 113.990418978 C (carbon) | 17 | 12.011 | 17 × 12.011 = 204.187 O (oxygen) | 4 | 15.999 | 4 × 15.999 = 63.996 H (hydrogen) | 10 | 1.008 | 10 × 1.008 = 10.080 M = 113.990418978 g/mol + 204.187 g/mol + 63.996 g/mol + 10.080 g/mol = 392.253 g/mol
Unit conversion
![0.3922 kg/mol (kilograms per mole)](../image_source/8e014ba017a135a501bd2202ff507d89.png)
0.3922 kg/mol (kilograms per mole)
Comparisons
![≈ 0.54 × molar mass of fullerene ( ≈ 721 g/mol )](../image_source/1e0e5b2aa64455d10fd5465c04dc6c83.png)
≈ 0.54 × molar mass of fullerene ( ≈ 721 g/mol )
![≈ 2 × molar mass of caffeine ( ≈ 194 g/mol )](../image_source/5d2d7422bdc49954381d610107fad9bd.png)
≈ 2 × molar mass of caffeine ( ≈ 194 g/mol )
![≈ 6.7 × molar mass of sodium chloride ( ≈ 58 g/mol )](../image_source/6a8f88fc7da6992b83eeebe3524e542a.png)
≈ 6.7 × molar mass of sodium chloride ( ≈ 58 g/mol )
Corresponding quantities
![Mass of a molecule m from m = M/N_A: | 6.5×10^-22 grams | 6.5×10^-25 kg (kilograms) | 392 u (unified atomic mass units) | 392 Da (daltons)](../image_source/04cbec50f4dbd227f1d0b0410e198cf0.png)
Mass of a molecule m from m = M/N_A: | 6.5×10^-22 grams | 6.5×10^-25 kg (kilograms) | 392 u (unified atomic mass units) | 392 Da (daltons)
![Relative molecular mass M_r from M_r = M_u/M: | 392](../image_source/0656c74926ece64626d89f335d55c15b.png)
Relative molecular mass M_r from M_r = M_u/M: | 392