Input interpretation
cesium orthovanadate | molar mass
Result
Find the molar mass, M, for cesium orthovanadate: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: Cs_3VO_4 Use the chemical formula to count the number of atoms, N_i, for each element: | N_i Cs (cesium) | 3 O (oxygen) | 4 V (vanadium) | 1 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) Cs (cesium) | 3 | 132.90545196 O (oxygen) | 4 | 15.999 V (vanadium) | 1 | 50.9415 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) Cs (cesium) | 3 | 132.90545196 | 3 × 132.90545196 = 398.71635588 O (oxygen) | 4 | 15.999 | 4 × 15.999 = 63.996 V (vanadium) | 1 | 50.9415 | 1 × 50.9415 = 50.9415 M = 398.71635588 g/mol + 63.996 g/mol + 50.9415 g/mol = 513.654 g/mol
Unit conversion
0.513654 kg/mol (kilograms per mole)
Comparisons
≈ 0.71 × molar mass of fullerene ( ≈ 721 g/mol )
≈ 2.6 × molar mass of caffeine ( ≈ 194 g/mol )
≈ 8.8 × molar mass of sodium chloride ( ≈ 58 g/mol )
Corresponding quantities
Mass of a molecule m from m = M/N_A: | 8.5×10^-22 grams | 8.5×10^-25 kg (kilograms) | 514 u (unified atomic mass units) | 514 Da (daltons)
Relative molecular mass M_r from M_r = M_u/M: | 514