Input interpretation
cadmium borate | molar mass
Result
Find the molar mass, M, for cadmium borate: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: B_2Cd_3O_6 Use the chemical formula, B_2Cd_3O_6, to count the number of atoms, N_i, for each element: | N_i B (boron) | 2 Cd (cadmium) | 3 O (oxygen) | 6 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) B (boron) | 2 | 10.81 Cd (cadmium) | 3 | 112.414 O (oxygen) | 6 | 15.999 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) B (boron) | 2 | 10.81 | 2 × 10.81 = 21.62 Cd (cadmium) | 3 | 112.414 | 3 × 112.414 = 337.242 O (oxygen) | 6 | 15.999 | 6 × 15.999 = 95.994 M = 21.62 g/mol + 337.242 g/mol + 95.994 g/mol = 454.86 g/mol
Unit conversion
0.45486 kg/mol (kilograms per mole)
Comparisons
≈ 0.63 × molar mass of fullerene ( ≈ 721 g/mol )
≈ 2.3 × molar mass of caffeine ( ≈ 194 g/mol )
≈ 7.8 × molar mass of sodium chloride ( ≈ 58 g/mol )
Corresponding quantities
Mass of a molecule m from m = M/N_A: | 7.6×10^-22 grams | 7.6×10^-25 kg (kilograms) | 455 u (unified atomic mass units) | 455 Da (daltons)
Relative molecular mass M_r from M_r = M_u/M: | 455