2-fluoro-5-isopropoxyphenylboronic acid

2-fluoro-5-isopropoxyphenylboronic acid

formula | C_9H_12BFO_3 name | 2-fluoro-5-isopropoxyphenylboronic acid IUPAC name | (2-fluoro-5-isopropoxyphenyl)boronic acid alternate names | (2-fluoro-5-isopropoxy-phenyl)boronic acid | (2-fluoro-5-propan-2-yloxy-phenyl)boronic acid | (2-fluoro-5-propan-2-yloxyphenyl)boronic acid mass fractions | B (boron) 5.46% | C (carbon) 54.6% | F (fluorine) 9.6% | H (hydrogen) 6.11% | O (oxygen) 24.2%

Draw the Lewis structure of 2-fluoro-5-isopropoxyphenylboronic acid. Start by drawing the overall structure of the molecule, ignoring potential double and triple bonds: Count the total valence electrons of the boron (n_B, val = 3), carbon (n_C, val = 4), fluorine (n_F, val = 7), hydrogen (n_H, val = 1), and oxygen (n_O, val = 6) atoms: n_B, val + 9 n_C, val + n_F, val + 12 n_H, val + 3 n_O, val = 76 Calculate the number of electrons needed to completely fill the valence shells for boron (n_B, full = 6), carbon (n_C, full = 8), fluorine (n_F, full = 8), hydrogen (n_H, full = 2), and oxygen (n_O, full = 8): n_B, full + 9 n_C, full + n_F, full + 12 n_H, full + 3 n_O, full = 134 Subtracting these two numbers shows that 134 - 76 = 58 bonding electrons are needed. Each bond has two electrons, so in addition to the 26 bonds already present in the diagram add 3 bonds. To minimize formal charge carbon wants 4 bonds. Identify the atoms that want additional bonds and the number of electrons remaining on each atom: Fill in the 3 bonds by pairing electrons between adjacent highlighted atoms. Note that the six atom ring is aromatic, so that the single and double bonds may be rearranged: Answer: | |

molar mass | 198 g/mol phase | solid (at STP) melting point | 87.5 °C

CAS number | 849062-30-2 PubChem CID number | 16217681 PubChem SID number | 24882673 SMILES identifier | B(C1=C(C=CC(=C1)OC(C)C)F)(O)O InChI identifier | InChI=1/C9H12BFO3/c1-6(2)14-7-3-4-9(11)8(5-7)10(12)13/h3-6, 12-13H, 1-2H3 MDL number | MFCD06411349