Input interpretation
![barium chlorate | molar mass](../image_source/98eb48b12fed57b9f0f648ed960bad51.png)
barium chlorate | molar mass
Result
![Find the molar mass, M, for barium chlorate: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: BaCl_2O_6 Use the chemical formula to count the number of atoms, N_i, for each element: | N_i Ba (barium) | 1 Cl (chlorine) | 2 O (oxygen) | 6 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) Ba (barium) | 1 | 137.327 Cl (chlorine) | 2 | 35.45 O (oxygen) | 6 | 15.999 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) Ba (barium) | 1 | 137.327 | 1 × 137.327 = 137.327 Cl (chlorine) | 2 | 35.45 | 2 × 35.45 = 70.90 O (oxygen) | 6 | 15.999 | 6 × 15.999 = 95.994 M = 137.327 g/mol + 70.90 g/mol + 95.994 g/mol = 304.22 g/mol](../image_source/44892f741d6faccc88374f5ad0cde936.png)
Find the molar mass, M, for barium chlorate: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: BaCl_2O_6 Use the chemical formula to count the number of atoms, N_i, for each element: | N_i Ba (barium) | 1 Cl (chlorine) | 2 O (oxygen) | 6 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) Ba (barium) | 1 | 137.327 Cl (chlorine) | 2 | 35.45 O (oxygen) | 6 | 15.999 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) Ba (barium) | 1 | 137.327 | 1 × 137.327 = 137.327 Cl (chlorine) | 2 | 35.45 | 2 × 35.45 = 70.90 O (oxygen) | 6 | 15.999 | 6 × 15.999 = 95.994 M = 137.327 g/mol + 70.90 g/mol + 95.994 g/mol = 304.22 g/mol
Unit conversion
![0.30422 kg/mol (kilograms per mole)](../image_source/c42df13d8e0cfb2ad9f583381ba4d6f7.png)
0.30422 kg/mol (kilograms per mole)
Comparisons
![≈ 0.42 × molar mass of fullerene ( ≈ 721 g/mol )](../image_source/74c03d284c532fa41363c68f12982ca1.png)
≈ 0.42 × molar mass of fullerene ( ≈ 721 g/mol )
![≈ 1.6 × molar mass of caffeine ( ≈ 194 g/mol )](../image_source/5d861205e3572bbcdd0cb1c1bc5c20a8.png)
≈ 1.6 × molar mass of caffeine ( ≈ 194 g/mol )
![≈ 5.2 × molar mass of sodium chloride ( ≈ 58 g/mol )](../image_source/e9c2bcfc00380d339b59d5791b11ab38.png)
≈ 5.2 × molar mass of sodium chloride ( ≈ 58 g/mol )
Corresponding quantities
![Mass of a molecule m from m = M/N_A: | 5.1×10^-22 grams | 5.1×10^-25 kg (kilograms) | 304 u (unified atomic mass units) | 304 Da (daltons)](../image_source/e3fe44c3cd0a4446af3228c31ff5b447.png)
Mass of a molecule m from m = M/N_A: | 5.1×10^-22 grams | 5.1×10^-25 kg (kilograms) | 304 u (unified atomic mass units) | 304 Da (daltons)
![Relative molecular mass M_r from M_r = M_u/M: | 304](../image_source/7f5c7c9de2699b34ffdbd7747d462a26.png)
Relative molecular mass M_r from M_r = M_u/M: | 304