Input interpretation
pentahydrogenorthotellurate anion
Lewis structure
Draw the Lewis structure of pentahydrogenorthotellurate anion. Start by drawing the overall structure of the molecule: Count the total valence electrons of the hydrogen (n_H, val = 1), oxygen (n_O, val = 6), and tellurium (n_Te, val = 6) atoms, including the net charge: 5 n_H, val + 6 n_O, val + n_Te, val - n_charge = 48 Calculate the number of electrons needed to completely fill the valence shells for hydrogen (n_H, full = 2), oxygen (n_O, full = 8), and tellurium (n_Te, full = 8): 5 n_H, full + 6 n_O, full + n_Te, full = 66 Subtracting these two numbers shows that 66 - 48 = 18 bonding electrons are needed, which are already accounted for in the structure. Note that the valence shell of tellurium has been expanded to 6 bonds. After accounting for the expanded valence, there are 11 bonds and hence 22 bonding electrons in the diagram. Fill in the remaining unbonded electrons on each atom. In total, there remain 48 - 22 = 26 electrons left to draw. Lastly, fill in the formal charges: Answer: | |
General properties
formula | (H_5TeO_6)^- net ionic charge | -1 alternate names | pentahydrogenorthotellurate | pentahydrogenorthotellurate(1-)
Other properties
ion class | anions | oxoanions | polyatomic ions