Input interpretation
hydrogen chloride + selenic acid ⟶ water + chlorine + selenious acid
Balanced equation
Balance the chemical equation algebraically: + ⟶ + + Add stoichiometric coefficients, c_i, to the reactants and products: c_1 + c_2 ⟶ c_3 + c_4 + c_5 Set the number of atoms in the reactants equal to the number of atoms in the products for Cl, H, O and Se: Cl: | c_1 = 2 c_4 H: | c_1 + 2 c_2 = 2 c_3 + 2 c_5 O: | 4 c_2 = c_3 + 3 c_5 Se: | c_2 = c_5 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_2 = 1 and solve the system of equations for the remaining coefficients: c_1 = 2 c_2 = 1 c_3 = 1 c_4 = 1 c_5 = 1 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | 2 + ⟶ + +
Structures
+ ⟶ + +
Names
hydrogen chloride + selenic acid ⟶ water + chlorine + selenious acid
Chemical names and formulas
| hydrogen chloride | selenic acid | water | chlorine | selenious acid Hill formula | ClH | H_2O_4Se | H_2O | Cl_2 | H_2O_3Se name | hydrogen chloride | selenic acid | water | chlorine | selenious acid IUPAC name | hydrogen chloride | selenic acid | water | molecular chlorine | selenous acid