krypton difluoride

krypton difluoride

formula | F_2Kr_1 Hill formula | F_2Kr name | krypton difluoride IUPAC name | difluorokrypton mass fractions | F (fluorine) 31.2% | Kr (krypton) 68.8%

Draw the Lewis structure of krypton difluoride. Start by drawing the overall structure of the molecule: Count the total valence electrons of the fluorine (n_F, val = 7) and krypton (n_Kr, val = 8) atoms: 2 n_F, val + n_Kr, val = 22 Calculate the number of electrons needed to completely fill the valence shells for fluorine (n_F, full = 8) and krypton (n_Kr, full = 8): 2 n_F, full + n_Kr, full = 24 Subtracting these two numbers shows that 24 - 22 = 2 bonding electrons are needed, which are already accounted for in the structure. Note that the valence shell of krypton has been expanded. After accounting for the expanded valence, there are 2 bonds and hence 4 bonding electrons in the diagram. Lastly, fill in the remaining unbonded electrons on each atom. In total, there remain 22 - 4 = 18 electrons left to draw: Answer: | |

molar mass | 121.79 g/mol

PubChem CID number | 83721 SMILES identifier | F[Kr]F InChI identifier | InChI=1S/F2Kr/c1-3-2