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molar mass of phenyl(tribromomethyl)mercury

Input interpretation

phenyl(tribromomethyl)mercury | molar mass
phenyl(tribromomethyl)mercury | molar mass

Result

Find the molar mass, M, for phenyl(tribromomethyl)mercury: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: C_7H_5Br_3Hg Use the chemical formula, C_7H_5Br_3Hg, to count the number of atoms, N_i, for each element:  | N_i  Br (bromine) | 3  C (carbon) | 7  H (hydrogen) | 5  Hg (mercury) | 1 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table:  | N_i | m_i/g·mol^(-1)  Br (bromine) | 3 | 79.904  C (carbon) | 7 | 12.011  H (hydrogen) | 5 | 1.008  Hg (mercury) | 1 | 200.592 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: |   | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1)  Br (bromine) | 3 | 79.904 | 3 × 79.904 = 239.712  C (carbon) | 7 | 12.011 | 7 × 12.011 = 84.077  H (hydrogen) | 5 | 1.008 | 5 × 1.008 = 5.040  Hg (mercury) | 1 | 200.592 | 1 × 200.592 = 200.592  M = 239.712 g/mol + 84.077 g/mol + 5.040 g/mol + 200.592 g/mol = 529.421 g/mol
Find the molar mass, M, for phenyl(tribromomethyl)mercury: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: C_7H_5Br_3Hg Use the chemical formula, C_7H_5Br_3Hg, to count the number of atoms, N_i, for each element: | N_i Br (bromine) | 3 C (carbon) | 7 H (hydrogen) | 5 Hg (mercury) | 1 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) Br (bromine) | 3 | 79.904 C (carbon) | 7 | 12.011 H (hydrogen) | 5 | 1.008 Hg (mercury) | 1 | 200.592 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) Br (bromine) | 3 | 79.904 | 3 × 79.904 = 239.712 C (carbon) | 7 | 12.011 | 7 × 12.011 = 84.077 H (hydrogen) | 5 | 1.008 | 5 × 1.008 = 5.040 Hg (mercury) | 1 | 200.592 | 1 × 200.592 = 200.592 M = 239.712 g/mol + 84.077 g/mol + 5.040 g/mol + 200.592 g/mol = 529.421 g/mol

Unit conversion

0.52942 kg/mol (kilograms per mole)
0.52942 kg/mol (kilograms per mole)

Comparisons

 ≈ 0.73 × molar mass of fullerene ( ≈ 721 g/mol )
≈ 0.73 × molar mass of fullerene ( ≈ 721 g/mol )
 ≈ 2.7 × molar mass of caffeine ( ≈ 194 g/mol )
≈ 2.7 × molar mass of caffeine ( ≈ 194 g/mol )
 ≈ 9.1 × molar mass of sodium chloride ( ≈ 58 g/mol )
≈ 9.1 × molar mass of sodium chloride ( ≈ 58 g/mol )

Corresponding quantities

Mass of a molecule m from m = M/N_A:  | 8.8×10^-22 grams  | 8.8×10^-25 kg (kilograms)  | 529 u (unified atomic mass units)  | 529 Da (daltons)
Mass of a molecule m from m = M/N_A: | 8.8×10^-22 grams | 8.8×10^-25 kg (kilograms) | 529 u (unified atomic mass units) | 529 Da (daltons)
Relative molecular mass M_r from M_r = M_u/M:  | 529
Relative molecular mass M_r from M_r = M_u/M: | 529