Input interpretation
lithium selenite monohydrate | molar mass
Result
Find the molar mass, M, for lithium selenite monohydrate: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: Li_2SeO_3·H_2O Use the chemical formula to count the number of atoms, N_i, for each element: | N_i H (hydrogen) | 2 Li (lithium) | 2 O (oxygen) | 4 Se (selenium) | 1 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) H (hydrogen) | 2 | 1.008 Li (lithium) | 2 | 6.94 O (oxygen) | 4 | 15.999 Se (selenium) | 1 | 78.971 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) H (hydrogen) | 2 | 1.008 | 2 × 1.008 = 2.016 Li (lithium) | 2 | 6.94 | 2 × 6.94 = 13.88 O (oxygen) | 4 | 15.999 | 4 × 15.999 = 63.996 Se (selenium) | 1 | 78.971 | 1 × 78.971 = 78.971 M = 2.016 g/mol + 13.88 g/mol + 63.996 g/mol + 78.971 g/mol = 158.86 g/mol
Unit conversion
0.1589 kg/mol (kilograms per mole)
Comparisons
≈ ( 0.22 ≈ 1/5 ) × molar mass of fullerene ( ≈ 721 g/mol )
≈ 0.82 × molar mass of caffeine ( ≈ 194 g/mol )
≈ 2.7 × molar mass of sodium chloride ( ≈ 58 g/mol )
Corresponding quantities
Mass of a molecule m from m = M/N_A: | 2.6×10^-22 grams | 2.6×10^-25 kg (kilograms) | 159 u (unified atomic mass units) | 159 Da (daltons)
Relative molecular mass M_r from M_r = M_u/M: | 159