Input interpretation
![teriparatide | molar mass](../image_source/1be6d3d1b910179ed15920ddc81261bc.png)
teriparatide | molar mass
Result
![Find the molar mass, M, for teriparatide: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: C_181H_291N_55O_51S_2 Use the chemical formula to count the number of atoms, N_i, for each element: | N_i C (carbon) | 181 H (hydrogen) | 291 N (nitrogen) | 55 O (oxygen) | 51 S (sulfur) | 2 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) C (carbon) | 181 | 12.011 H (hydrogen) | 291 | 1.008 N (nitrogen) | 55 | 14.007 O (oxygen) | 51 | 15.999 S (sulfur) | 2 | 32.06 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) C (carbon) | 181 | 12.011 | 181 × 12.011 = 2173.991 H (hydrogen) | 291 | 1.008 | 291 × 1.008 = 293.328 N (nitrogen) | 55 | 14.007 | 55 × 14.007 = 770.385 O (oxygen) | 51 | 15.999 | 51 × 15.999 = 815.949 S (sulfur) | 2 | 32.06 | 2 × 32.06 = 64.12 M = 2173.991 g/mol + 293.328 g/mol + 770.385 g/mol + 815.949 g/mol + 64.12 g/mol = 4117.77 g/mol](../image_source/ce3b40556f81180c26e0ec601ca11ed2.png)
Find the molar mass, M, for teriparatide: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: C_181H_291N_55O_51S_2 Use the chemical formula to count the number of atoms, N_i, for each element: | N_i C (carbon) | 181 H (hydrogen) | 291 N (nitrogen) | 55 O (oxygen) | 51 S (sulfur) | 2 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) C (carbon) | 181 | 12.011 H (hydrogen) | 291 | 1.008 N (nitrogen) | 55 | 14.007 O (oxygen) | 51 | 15.999 S (sulfur) | 2 | 32.06 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) C (carbon) | 181 | 12.011 | 181 × 12.011 = 2173.991 H (hydrogen) | 291 | 1.008 | 291 × 1.008 = 293.328 N (nitrogen) | 55 | 14.007 | 55 × 14.007 = 770.385 O (oxygen) | 51 | 15.999 | 51 × 15.999 = 815.949 S (sulfur) | 2 | 32.06 | 2 × 32.06 = 64.12 M = 2173.991 g/mol + 293.328 g/mol + 770.385 g/mol + 815.949 g/mol + 64.12 g/mol = 4117.77 g/mol
Unit conversion
![4.1178 kg/mol (kilograms per mole)](../image_source/97f9124f33b77aba37669c4659706dc0.png)
4.1178 kg/mol (kilograms per mole)
Comparisons
![≈ 5.7 × molar mass of fullerene ( ≈ 721 g/mol )](../image_source/66238527d8347d414f065c2cfb91a31f.png)
≈ 5.7 × molar mass of fullerene ( ≈ 721 g/mol )
![≈ 21 × molar mass of caffeine ( ≈ 194 g/mol )](../image_source/04e4e55892e26232953dddd70c8300e8.png)
≈ 21 × molar mass of caffeine ( ≈ 194 g/mol )
![≈ 70 × molar mass of sodium chloride ( ≈ 58 g/mol )](../image_source/072c14e7bc8144c3ae608bdfcd399191.png)
≈ 70 × molar mass of sodium chloride ( ≈ 58 g/mol )
Corresponding quantities
![Mass of a molecule m from m = M/N_A: | 6.8×10^-21 grams | 6.8×10^-24 kg (kilograms) | 4118 u (unified atomic mass units) | 4.1 kDa (kilodaltons)](../image_source/0efd12bd68a6fd97aa54222f96b2c704.png)
Mass of a molecule m from m = M/N_A: | 6.8×10^-21 grams | 6.8×10^-24 kg (kilograms) | 4118 u (unified atomic mass units) | 4.1 kDa (kilodaltons)
![Relative molecular mass M_r from M_r = M_u/M: | 4118](../image_source/8e81f5c6f023678b7e9f55a85b8a8c65.png)
Relative molecular mass M_r from M_r = M_u/M: | 4118