mass fractions of silver chloride

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silver chloride | elemental composition

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$Find the elemental composition for silver chloride in terms of the atom and mass percents: atom percent = N_i/N_atoms × 100% mass percent = (N_im_i)/m × 100% Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i, m_i, N_atoms and m using these items. • Finally, compute the percents and check the results. Write the chemical formula: AgCl Use the chemical formula to count the number of atoms, N_i, for each element and find the total number of atoms, N_atoms, per molecule: | number of atoms Ag (silver) | 1 Cl (chlorine) | 1 N_atoms = 1 + 1 = 2 Divide each N_i by N_atoms to calculate atom fractions. Then use the property that atom fractions must sum to one to check the work: | number of atoms | atom fraction Ag (silver) | 1 | 1/2 Cl (chlorine) | 1 | 1/2 Check: 1/2 + 1/2 = 1 Compute atom percents using the atom fractions: | number of atoms | atom percent Ag (silver) | 1 | 1/2 × 100% = 50.0% Cl (chlorine) | 1 | 1/2 × 100% = 50.0% Look up the atomic mass, m_i, in unified atomic mass units, u, for each element in the periodic table: | number of atoms | atom percent | atomic mass/u Ag (silver) | 1 | 50.0% | 107.8682 Cl (chlorine) | 1 | 50.0% | 35.45 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molecular mass, m: | number of atoms | atom percent | atomic mass/u | mass/u Ag (silver) | 1 | 50.0% | 107.8682 | 1 × 107.8682 = 107.8682 Cl (chlorine) | 1 | 50.0% | 35.45 | 1 × 35.45 = 35.45 m = 107.8682 u + 35.45 u = 143.3182 u Divide the mass for each element by m to calculate mass fractions. Then use the property that mass fractions must sum to one to check the work: | number of atoms | atom percent | mass fraction Ag (silver) | 1 | 50.0% | 107.8682/143.3182 Cl (chlorine) | 1 | 50.0% | 35.45/143.3182 Check: 107.8682/143.3182 + 35.45/143.3182 = 1 Compute mass percents using the mass fractions: Answer: | | | number of atoms | atom percent | mass percent Ag (silver) | 1 | 50.0% | 107.8682/143.3182 × 100% = 75.26% Cl (chlorine) | 1 | 50.0% | 35.45/143.3182 × 100% = 24.74%$

Find the elemental composition for silver chloride in terms of the atom and mass percents: atom percent = N_i/N_atoms × 100% mass percent = (N_im_i)/m × 100% Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i, m_i, N_atoms and m using these items. • Finally, compute the percents and check the results. Write the chemical formula: AgCl Use the chemical formula to count the number of atoms, N_i, for each element and find the total number of atoms, N_atoms, per molecule: | number of atoms Ag (silver) | 1 Cl (chlorine) | 1 N_atoms = 1 + 1 = 2 Divide each N_i by N_atoms to calculate atom fractions. Then use the property that atom fractions must sum to one to check the work: | number of atoms | atom fraction Ag (silver) | 1 | 1/2 Cl (chlorine) | 1 | 1/2 Check: 1/2 + 1/2 = 1 Compute atom percents using the atom fractions: | number of atoms | atom percent Ag (silver) | 1 | 1/2 × 100% = 50.0% Cl (chlorine) | 1 | 1/2 × 100% = 50.0% Look up the atomic mass, m_i, in unified atomic mass units, u, for each element in the periodic table: | number of atoms | atom percent | atomic mass/u Ag (silver) | 1 | 50.0% | 107.8682 Cl (chlorine) | 1 | 50.0% | 35.45 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molecular mass, m: | number of atoms | atom percent | atomic mass/u | mass/u Ag (silver) | 1 | 50.0% | 107.8682 | 1 × 107.8682 = 107.8682 Cl (chlorine) | 1 | 50.0% | 35.45 | 1 × 35.45 = 35.45 m = 107.8682 u + 35.45 u = 143.3182 u Divide the mass for each element by m to calculate mass fractions. Then use the property that mass fractions must sum to one to check the work: | number of atoms | atom percent | mass fraction Ag (silver) | 1 | 50.0% | 107.8682/143.3182 Cl (chlorine) | 1 | 50.0% | 35.45/143.3182 Check: 107.8682/143.3182 + 35.45/143.3182 = 1 Compute mass percents using the mass fractions: Answer: | | | number of atoms | atom percent | mass percent Ag (silver) | 1 | 50.0% | 107.8682/143.3182 × 100% = 75.26% Cl (chlorine) | 1 | 50.0% | 35.45/143.3182 × 100% = 24.74%