Input interpretation
![2-fluorophenyl isocyanate | molar mass](../image_source/fac1c48b2dd0e59496e4f797ab4c61c2.png)
2-fluorophenyl isocyanate | molar mass
Result
![Find the molar mass, M, for 2-fluorophenyl isocyanate: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: FC_6H_4NCO Use the chemical formula to count the number of atoms, N_i, for each element: | N_i C (carbon) | 7 F (fluorine) | 1 H (hydrogen) | 4 N (nitrogen) | 1 O (oxygen) | 1 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) C (carbon) | 7 | 12.011 F (fluorine) | 1 | 18.998403163 H (hydrogen) | 4 | 1.008 N (nitrogen) | 1 | 14.007 O (oxygen) | 1 | 15.999 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) C (carbon) | 7 | 12.011 | 7 × 12.011 = 84.077 F (fluorine) | 1 | 18.998403163 | 1 × 18.998403163 = 18.998403163 H (hydrogen) | 4 | 1.008 | 4 × 1.008 = 4.032 N (nitrogen) | 1 | 14.007 | 1 × 14.007 = 14.007 O (oxygen) | 1 | 15.999 | 1 × 15.999 = 15.999 M = 84.077 g/mol + 18.998403163 g/mol + 4.032 g/mol + 14.007 g/mol + 15.999 g/mol = 137.113 g/mol](../image_source/0a790c30e13f0b6352782ea29ed5c1cf.png)
Find the molar mass, M, for 2-fluorophenyl isocyanate: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: FC_6H_4NCO Use the chemical formula to count the number of atoms, N_i, for each element: | N_i C (carbon) | 7 F (fluorine) | 1 H (hydrogen) | 4 N (nitrogen) | 1 O (oxygen) | 1 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) C (carbon) | 7 | 12.011 F (fluorine) | 1 | 18.998403163 H (hydrogen) | 4 | 1.008 N (nitrogen) | 1 | 14.007 O (oxygen) | 1 | 15.999 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) C (carbon) | 7 | 12.011 | 7 × 12.011 = 84.077 F (fluorine) | 1 | 18.998403163 | 1 × 18.998403163 = 18.998403163 H (hydrogen) | 4 | 1.008 | 4 × 1.008 = 4.032 N (nitrogen) | 1 | 14.007 | 1 × 14.007 = 14.007 O (oxygen) | 1 | 15.999 | 1 × 15.999 = 15.999 M = 84.077 g/mol + 18.998403163 g/mol + 4.032 g/mol + 14.007 g/mol + 15.999 g/mol = 137.113 g/mol
Unit conversion
![0.13711 kg/mol (kilograms per mole)](../image_source/2467f7fcf56c6be5656ec8954e9c4c08.png)
0.13711 kg/mol (kilograms per mole)
Comparisons
![≈ ( 0.19 ≈ 1/5 ) × molar mass of fullerene ( ≈ 721 g/mol )](../image_source/d504a474cdd6c6619b5ae55730288395.png)
≈ ( 0.19 ≈ 1/5 ) × molar mass of fullerene ( ≈ 721 g/mol )
![≈ 0.71 × molar mass of caffeine ( ≈ 194 g/mol )](../image_source/603ca2ba46ce92104ca30412bd0ff484.png)
≈ 0.71 × molar mass of caffeine ( ≈ 194 g/mol )
![≈ 2.3 × molar mass of sodium chloride ( ≈ 58 g/mol )](../image_source/77e855f247d336508be95a9f747eb3fb.png)
≈ 2.3 × molar mass of sodium chloride ( ≈ 58 g/mol )
Corresponding quantities
![Mass of a molecule m from m = M/N_A: | 2.3×10^-22 grams | 2.3×10^-25 kg (kilograms) | 137 u (unified atomic mass units) | 137 Da (daltons)](../image_source/4bf72a9342c1446f6beb5122de0ad610.png)
Mass of a molecule m from m = M/N_A: | 2.3×10^-22 grams | 2.3×10^-25 kg (kilograms) | 137 u (unified atomic mass units) | 137 Da (daltons)
![Relative molecular mass M_r from M_r = M_u/M: | 137](../image_source/da807960c0d028923a33136dfa3a0e2c.png)
Relative molecular mass M_r from M_r = M_u/M: | 137