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molar mass of profenofos

Input interpretation

profenofos | molar mass
profenofos | molar mass

Result

Find the molar mass, M, for profenofos: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: C_11H_15BrClO_3PS Use the chemical formula to count the number of atoms, N_i, for each element:  | N_i  Br (bromine) | 1  C (carbon) | 11  Cl (chlorine) | 1  H (hydrogen) | 15  O (oxygen) | 3  P (phosphorus) | 1  S (sulfur) | 1 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table:  | N_i | m_i/g·mol^(-1)  Br (bromine) | 1 | 79.904  C (carbon) | 11 | 12.011  Cl (chlorine) | 1 | 35.45  H (hydrogen) | 15 | 1.008  O (oxygen) | 3 | 15.999  P (phosphorus) | 1 | 30.973761998  S (sulfur) | 1 | 32.06 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: |   | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1)  Br (bromine) | 1 | 79.904 | 1 × 79.904 = 79.904  C (carbon) | 11 | 12.011 | 11 × 12.011 = 132.121  Cl (chlorine) | 1 | 35.45 | 1 × 35.45 = 35.45  H (hydrogen) | 15 | 1.008 | 15 × 1.008 = 15.120  O (oxygen) | 3 | 15.999 | 3 × 15.999 = 47.997  P (phosphorus) | 1 | 30.973761998 | 1 × 30.973761998 = 30.973761998  S (sulfur) | 1 | 32.06 | 1 × 32.06 = 32.06  M = 79.904 g/mol + 132.121 g/mol + 35.45 g/mol + 15.120 g/mol + 47.997 g/mol + 30.973761998 g/mol + 32.06 g/mol = 373.63 g/mol
Find the molar mass, M, for profenofos: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: C_11H_15BrClO_3PS Use the chemical formula to count the number of atoms, N_i, for each element: | N_i Br (bromine) | 1 C (carbon) | 11 Cl (chlorine) | 1 H (hydrogen) | 15 O (oxygen) | 3 P (phosphorus) | 1 S (sulfur) | 1 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) Br (bromine) | 1 | 79.904 C (carbon) | 11 | 12.011 Cl (chlorine) | 1 | 35.45 H (hydrogen) | 15 | 1.008 O (oxygen) | 3 | 15.999 P (phosphorus) | 1 | 30.973761998 S (sulfur) | 1 | 32.06 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) Br (bromine) | 1 | 79.904 | 1 × 79.904 = 79.904 C (carbon) | 11 | 12.011 | 11 × 12.011 = 132.121 Cl (chlorine) | 1 | 35.45 | 1 × 35.45 = 35.45 H (hydrogen) | 15 | 1.008 | 15 × 1.008 = 15.120 O (oxygen) | 3 | 15.999 | 3 × 15.999 = 47.997 P (phosphorus) | 1 | 30.973761998 | 1 × 30.973761998 = 30.973761998 S (sulfur) | 1 | 32.06 | 1 × 32.06 = 32.06 M = 79.904 g/mol + 132.121 g/mol + 35.45 g/mol + 15.120 g/mol + 47.997 g/mol + 30.973761998 g/mol + 32.06 g/mol = 373.63 g/mol

Unit conversion

0.3736 kg/mol (kilograms per mole)
0.3736 kg/mol (kilograms per mole)

Comparisons

 ≈ 0.52 × molar mass of fullerene ( ≈ 721 g/mol )
≈ 0.52 × molar mass of fullerene ( ≈ 721 g/mol )
 ≈ 1.9 × molar mass of caffeine ( ≈ 194 g/mol )
≈ 1.9 × molar mass of caffeine ( ≈ 194 g/mol )
 ≈ 6.4 × molar mass of sodium chloride ( ≈ 58 g/mol )
≈ 6.4 × molar mass of sodium chloride ( ≈ 58 g/mol )

Corresponding quantities

Mass of a molecule m from m = M/N_A:  | 6.2×10^-22 grams  | 6.2×10^-25 kg (kilograms)  | 374 u (unified atomic mass units)  | 374 Da (daltons)
Mass of a molecule m from m = M/N_A: | 6.2×10^-22 grams | 6.2×10^-25 kg (kilograms) | 374 u (unified atomic mass units) | 374 Da (daltons)
Relative molecular mass M_r from M_r = M_u/M:  | 374
Relative molecular mass M_r from M_r = M_u/M: | 374