Input interpretation
![D-chloropropionic acid | molar mass](../image_source/ba91b4c67ac522915f9b3643f14c05f1.png)
D-chloropropionic acid | molar mass
Result
![Find the molar mass, M, for D-chloropropionic acid: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: CH_3CH(Cl)CO_2H Use the chemical formula to count the number of atoms, N_i, for each element: | N_i C (carbon) | 3 Cl (chlorine) | 1 H (hydrogen) | 5 O (oxygen) | 2 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) C (carbon) | 3 | 12.011 Cl (chlorine) | 1 | 35.45 H (hydrogen) | 5 | 1.008 O (oxygen) | 2 | 15.999 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) C (carbon) | 3 | 12.011 | 3 × 12.011 = 36.033 Cl (chlorine) | 1 | 35.45 | 1 × 35.45 = 35.45 H (hydrogen) | 5 | 1.008 | 5 × 1.008 = 5.040 O (oxygen) | 2 | 15.999 | 2 × 15.999 = 31.998 M = 36.033 g/mol + 35.45 g/mol + 5.040 g/mol + 31.998 g/mol = 108.52 g/mol](../image_source/065d98d9390f1518373f75e538a6c675.png)
Find the molar mass, M, for D-chloropropionic acid: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: CH_3CH(Cl)CO_2H Use the chemical formula to count the number of atoms, N_i, for each element: | N_i C (carbon) | 3 Cl (chlorine) | 1 H (hydrogen) | 5 O (oxygen) | 2 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) C (carbon) | 3 | 12.011 Cl (chlorine) | 1 | 35.45 H (hydrogen) | 5 | 1.008 O (oxygen) | 2 | 15.999 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) C (carbon) | 3 | 12.011 | 3 × 12.011 = 36.033 Cl (chlorine) | 1 | 35.45 | 1 × 35.45 = 35.45 H (hydrogen) | 5 | 1.008 | 5 × 1.008 = 5.040 O (oxygen) | 2 | 15.999 | 2 × 15.999 = 31.998 M = 36.033 g/mol + 35.45 g/mol + 5.040 g/mol + 31.998 g/mol = 108.52 g/mol
Unit conversion
![0.1085 kg/mol (kilograms per mole)](../image_source/55f72db511f15b4a1555f910d13bfe0f.png)
0.1085 kg/mol (kilograms per mole)
Comparisons
![≈ ( 0.15 ≈ 1/7 ) × molar mass of fullerene ( ≈ 721 g/mol )](../image_source/2508fc7f078bcf2b932fd5018e347712.png)
≈ ( 0.15 ≈ 1/7 ) × molar mass of fullerene ( ≈ 721 g/mol )
![≈ 0.56 × molar mass of caffeine ( ≈ 194 g/mol )](../image_source/50876e4cb0e908c421a8019477a670d1.png)
≈ 0.56 × molar mass of caffeine ( ≈ 194 g/mol )
![≈ 1.9 × molar mass of sodium chloride ( ≈ 58 g/mol )](../image_source/a9bcb4414d50cfea2449ce986da91ecc.png)
≈ 1.9 × molar mass of sodium chloride ( ≈ 58 g/mol )
Corresponding quantities
![Mass of a molecule m from m = M/N_A: | 1.8×10^-22 grams | 1.8×10^-25 kg (kilograms) | 109 u (unified atomic mass units) | 109 Da (daltons)](../image_source/de77de34d6d9aaebed051dc8ca4ec728.png)
Mass of a molecule m from m = M/N_A: | 1.8×10^-22 grams | 1.8×10^-25 kg (kilograms) | 109 u (unified atomic mass units) | 109 Da (daltons)
![Relative molecular mass M_r from M_r = M_u/M: | 109](../image_source/85076966a34b821fb6854e291b9f4bcd.png)
Relative molecular mass M_r from M_r = M_u/M: | 109