Input interpretation
![H_2S (hydrogen sulfide) + KNO_2 (potassium nitrite) ⟶ K2S + HNO_2 (nitrous acid)](../image_source/9a9c12cc489c14b120e840001bf89fca.png)
H_2S (hydrogen sulfide) + KNO_2 (potassium nitrite) ⟶ K2S + HNO_2 (nitrous acid)
Balanced equation
![Balance the chemical equation algebraically: H_2S + KNO_2 ⟶ K2S + HNO_2 Add stoichiometric coefficients, c_i, to the reactants and products: c_1 H_2S + c_2 KNO_2 ⟶ c_3 K2S + c_4 HNO_2 Set the number of atoms in the reactants equal to the number of atoms in the products for H, S, K, N and O: H: | 2 c_1 = c_4 S: | c_1 = c_3 K: | c_2 = 2 c_3 N: | c_2 = c_4 O: | 2 c_2 = 2 c_4 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_1 = 1 and solve the system of equations for the remaining coefficients: c_1 = 1 c_2 = 2 c_3 = 1 c_4 = 2 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | H_2S + 2 KNO_2 ⟶ K2S + 2 HNO_2](../image_source/2ef0d82a3c7ebf298188ce7005ad66b6.png)
Balance the chemical equation algebraically: H_2S + KNO_2 ⟶ K2S + HNO_2 Add stoichiometric coefficients, c_i, to the reactants and products: c_1 H_2S + c_2 KNO_2 ⟶ c_3 K2S + c_4 HNO_2 Set the number of atoms in the reactants equal to the number of atoms in the products for H, S, K, N and O: H: | 2 c_1 = c_4 S: | c_1 = c_3 K: | c_2 = 2 c_3 N: | c_2 = c_4 O: | 2 c_2 = 2 c_4 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_1 = 1 and solve the system of equations for the remaining coefficients: c_1 = 1 c_2 = 2 c_3 = 1 c_4 = 2 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | H_2S + 2 KNO_2 ⟶ K2S + 2 HNO_2
Structures
![+ ⟶ K2S +](../image_source/93f20c76fa26c174e7d54fc308af22ad.png)
+ ⟶ K2S +
Names
![hydrogen sulfide + potassium nitrite ⟶ K2S + nitrous acid](../image_source/b7036d5eb96fa831be6487d99c416a00.png)
hydrogen sulfide + potassium nitrite ⟶ K2S + nitrous acid
Equilibrium constant
![Construct the equilibrium constant, K, expression for: H_2S + KNO_2 ⟶ K2S + HNO_2 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the activity expression for each chemical species. • Use the activity expressions to build the equilibrium constant expression. Write the balanced chemical equation: H_2S + 2 KNO_2 ⟶ K2S + 2 HNO_2 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i H_2S | 1 | -1 KNO_2 | 2 | -2 K2S | 1 | 1 HNO_2 | 2 | 2 Assemble the activity expressions accounting for the state of matter and ν_i: chemical species | c_i | ν_i | activity expression H_2S | 1 | -1 | ([H2S])^(-1) KNO_2 | 2 | -2 | ([KNO2])^(-2) K2S | 1 | 1 | [K2S] HNO_2 | 2 | 2 | ([HNO2])^2 The equilibrium constant symbol in the concentration basis is: K_c Mulitply the activity expressions to arrive at the K_c expression: Answer: | | K_c = ([H2S])^(-1) ([KNO2])^(-2) [K2S] ([HNO2])^2 = ([K2S] ([HNO2])^2)/([H2S] ([KNO2])^2)](../image_source/a6c4e102aaf023b7511063ae66a8d3b9.png)
Construct the equilibrium constant, K, expression for: H_2S + KNO_2 ⟶ K2S + HNO_2 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the activity expression for each chemical species. • Use the activity expressions to build the equilibrium constant expression. Write the balanced chemical equation: H_2S + 2 KNO_2 ⟶ K2S + 2 HNO_2 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i H_2S | 1 | -1 KNO_2 | 2 | -2 K2S | 1 | 1 HNO_2 | 2 | 2 Assemble the activity expressions accounting for the state of matter and ν_i: chemical species | c_i | ν_i | activity expression H_2S | 1 | -1 | ([H2S])^(-1) KNO_2 | 2 | -2 | ([KNO2])^(-2) K2S | 1 | 1 | [K2S] HNO_2 | 2 | 2 | ([HNO2])^2 The equilibrium constant symbol in the concentration basis is: K_c Mulitply the activity expressions to arrive at the K_c expression: Answer: | | K_c = ([H2S])^(-1) ([KNO2])^(-2) [K2S] ([HNO2])^2 = ([K2S] ([HNO2])^2)/([H2S] ([KNO2])^2)
Rate of reaction
![Construct the rate of reaction expression for: H_2S + KNO_2 ⟶ K2S + HNO_2 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the rate term for each chemical species. • Write the rate of reaction expression. Write the balanced chemical equation: H_2S + 2 KNO_2 ⟶ K2S + 2 HNO_2 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i H_2S | 1 | -1 KNO_2 | 2 | -2 K2S | 1 | 1 HNO_2 | 2 | 2 The rate term for each chemical species, B_i, is 1/ν_i(Δ[B_i])/(Δt) where [B_i] is the amount concentration and t is time: chemical species | c_i | ν_i | rate term H_2S | 1 | -1 | -(Δ[H2S])/(Δt) KNO_2 | 2 | -2 | -1/2 (Δ[KNO2])/(Δt) K2S | 1 | 1 | (Δ[K2S])/(Δt) HNO_2 | 2 | 2 | 1/2 (Δ[HNO2])/(Δt) (for infinitesimal rate of change, replace Δ with d) Set the rate terms equal to each other to arrive at the rate expression: Answer: | | rate = -(Δ[H2S])/(Δt) = -1/2 (Δ[KNO2])/(Δt) = (Δ[K2S])/(Δt) = 1/2 (Δ[HNO2])/(Δt) (assuming constant volume and no accumulation of intermediates or side products)](../image_source/86838067f3c6879d25edd1dfc3d3eeec.png)
Construct the rate of reaction expression for: H_2S + KNO_2 ⟶ K2S + HNO_2 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the rate term for each chemical species. • Write the rate of reaction expression. Write the balanced chemical equation: H_2S + 2 KNO_2 ⟶ K2S + 2 HNO_2 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i H_2S | 1 | -1 KNO_2 | 2 | -2 K2S | 1 | 1 HNO_2 | 2 | 2 The rate term for each chemical species, B_i, is 1/ν_i(Δ[B_i])/(Δt) where [B_i] is the amount concentration and t is time: chemical species | c_i | ν_i | rate term H_2S | 1 | -1 | -(Δ[H2S])/(Δt) KNO_2 | 2 | -2 | -1/2 (Δ[KNO2])/(Δt) K2S | 1 | 1 | (Δ[K2S])/(Δt) HNO_2 | 2 | 2 | 1/2 (Δ[HNO2])/(Δt) (for infinitesimal rate of change, replace Δ with d) Set the rate terms equal to each other to arrive at the rate expression: Answer: | | rate = -(Δ[H2S])/(Δt) = -1/2 (Δ[KNO2])/(Δt) = (Δ[K2S])/(Δt) = 1/2 (Δ[HNO2])/(Δt) (assuming constant volume and no accumulation of intermediates or side products)
Chemical names and formulas
![| hydrogen sulfide | potassium nitrite | K2S | nitrous acid formula | H_2S | KNO_2 | K2S | HNO_2 name | hydrogen sulfide | potassium nitrite | | nitrous acid](../image_source/09d9e4a5d72159a43c90a53c88b724a3.png)
| hydrogen sulfide | potassium nitrite | K2S | nitrous acid formula | H_2S | KNO_2 | K2S | HNO_2 name | hydrogen sulfide | potassium nitrite | | nitrous acid
Substance properties
![| hydrogen sulfide | potassium nitrite | K2S | nitrous acid molar mass | 34.08 g/mol | 85.103 g/mol | 110.26 g/mol | 47.013 g/mol phase | gas (at STP) | solid (at STP) | | melting point | -85 °C | 350 °C | | boiling point | -60 °C | | | density | 0.001393 g/cm^3 (at 25 °C) | 1.915 g/cm^3 | | dynamic viscosity | 1.239×10^-5 Pa s (at 25 °C) | | |](../image_source/dfa884a3aaed996416f74026303839c1.png)
| hydrogen sulfide | potassium nitrite | K2S | nitrous acid molar mass | 34.08 g/mol | 85.103 g/mol | 110.26 g/mol | 47.013 g/mol phase | gas (at STP) | solid (at STP) | | melting point | -85 °C | 350 °C | | boiling point | -60 °C | | | density | 0.001393 g/cm^3 (at 25 °C) | 1.915 g/cm^3 | | dynamic viscosity | 1.239×10^-5 Pa s (at 25 °C) | | |
Units