Input interpretation
![fluorocyclohexane | molar mass](../image_source/1e329c488a1ac68219c038361248f641.png)
fluorocyclohexane | molar mass
Result
![Find the molar mass, M, for fluorocyclohexane: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: C_6H_11F Use the chemical formula to count the number of atoms, N_i, for each element: | N_i C (carbon) | 6 F (fluorine) | 1 H (hydrogen) | 11 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) C (carbon) | 6 | 12.011 F (fluorine) | 1 | 18.998403163 H (hydrogen) | 11 | 1.008 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) C (carbon) | 6 | 12.011 | 6 × 12.011 = 72.066 F (fluorine) | 1 | 18.998403163 | 1 × 18.998403163 = 18.998403163 H (hydrogen) | 11 | 1.008 | 11 × 1.008 = 11.088 M = 72.066 g/mol + 18.998403163 g/mol + 11.088 g/mol = 102.152 g/mol](../image_source/74e2215bdc1438163d6edc102ed09e1f.png)
Find the molar mass, M, for fluorocyclohexane: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: C_6H_11F Use the chemical formula to count the number of atoms, N_i, for each element: | N_i C (carbon) | 6 F (fluorine) | 1 H (hydrogen) | 11 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) C (carbon) | 6 | 12.011 F (fluorine) | 1 | 18.998403163 H (hydrogen) | 11 | 1.008 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) C (carbon) | 6 | 12.011 | 6 × 12.011 = 72.066 F (fluorine) | 1 | 18.998403163 | 1 × 18.998403163 = 18.998403163 H (hydrogen) | 11 | 1.008 | 11 × 1.008 = 11.088 M = 72.066 g/mol + 18.998403163 g/mol + 11.088 g/mol = 102.152 g/mol
Unit conversion
![0.10215 kg/mol (kilograms per mole)](../image_source/9f6f60bbeee0f4c828334515b0d2bc9d.png)
0.10215 kg/mol (kilograms per mole)
Comparisons
![≈ ( 0.14 ≈ 1/7 ) × molar mass of fullerene ( ≈ 721 g/mol )](../image_source/c9f791e0b7e265a68f68bd9be9b80dec.png)
≈ ( 0.14 ≈ 1/7 ) × molar mass of fullerene ( ≈ 721 g/mol )
![≈ 0.53 × molar mass of caffeine ( ≈ 194 g/mol )](../image_source/a87dd9bd65f8104ebbb6311fac9c62ea.png)
≈ 0.53 × molar mass of caffeine ( ≈ 194 g/mol )
![≈ 1.7 × molar mass of sodium chloride ( ≈ 58 g/mol )](../image_source/68ac3f96c50417da5048e11343a176f0.png)
≈ 1.7 × molar mass of sodium chloride ( ≈ 58 g/mol )
Corresponding quantities
![Mass of a molecule m from m = M/N_A: | 1.7×10^-22 grams | 1.7×10^-25 kg (kilograms) | 102 u (unified atomic mass units) | 102 Da (daltons)](../image_source/c512e4f4fca3c301d9c006f369a9d1c1.png)
Mass of a molecule m from m = M/N_A: | 1.7×10^-22 grams | 1.7×10^-25 kg (kilograms) | 102 u (unified atomic mass units) | 102 Da (daltons)
![Relative molecular mass M_r from M_r = M_u/M: | 102](../image_source/3c921ccbe8a6934c158182983996dd3d.png)
Relative molecular mass M_r from M_r = M_u/M: | 102