H2O + Br2 + As2O3 = HBr + H3AsO4

water + bromine + arsenic trioxide ⟶ hydrogen bromide + arsenic acid, solid

Balance the chemical equation algebraically: + + ⟶ + Add stoichiometric coefficients, c_i, to the reactants and products: c_1 + c_2 + c_3 ⟶ c_4 + c_5 Set the number of atoms in the reactants equal to the number of atoms in the products for H, O, Br and As: H: | 2 c_1 = c_4 + 3 c_5 O: | c_1 + 3 c_3 = 4 c_5 Br: | 2 c_2 = c_4 As: | 2 c_3 = c_5 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_3 = 1 and solve the system of equations for the remaining coefficients: c_1 = 5 c_2 = 2 c_3 = 1 c_4 = 4 c_5 = 2 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | 5 + 2 + ⟶ 4 + 2

+ + ⟶ +

water + bromine + arsenic trioxide ⟶ hydrogen bromide + arsenic acid, solid

| water | bromine | arsenic trioxide | hydrogen bromide | arsenic acid, solid Hill formula | H_2O | Br_2 | As_2O_3 | BrH | AsH_3O_4 name | water | bromine | arsenic trioxide | hydrogen bromide | arsenic acid, solid IUPAC name | water | molecular bromine | 2, 4, 5-trioxa-1, 3-diarsabicyclo[1.1.1]pentane | hydrogen bromide | arsoric acid