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H2SO4 + Ba = H2 + BaSO4

Input interpretation

H_2SO_4 sulfuric acid + Ba barium ⟶ H_2 hydrogen + BaSO_4 barium sulfate
H_2SO_4 sulfuric acid + Ba barium ⟶ H_2 hydrogen + BaSO_4 barium sulfate

Balanced equation

Balance the chemical equation algebraically: H_2SO_4 + Ba ⟶ H_2 + BaSO_4 Add stoichiometric coefficients, c_i, to the reactants and products: c_1 H_2SO_4 + c_2 Ba ⟶ c_3 H_2 + c_4 BaSO_4 Set the number of atoms in the reactants equal to the number of atoms in the products for H, O, S and Ba: H: | 2 c_1 = 2 c_3 O: | 4 c_1 = 4 c_4 S: | c_1 = c_4 Ba: | c_2 = c_4 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_1 = 1 and solve the system of equations for the remaining coefficients: c_1 = 1 c_2 = 1 c_3 = 1 c_4 = 1 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: |   | H_2SO_4 + Ba ⟶ H_2 + BaSO_4
Balance the chemical equation algebraically: H_2SO_4 + Ba ⟶ H_2 + BaSO_4 Add stoichiometric coefficients, c_i, to the reactants and products: c_1 H_2SO_4 + c_2 Ba ⟶ c_3 H_2 + c_4 BaSO_4 Set the number of atoms in the reactants equal to the number of atoms in the products for H, O, S and Ba: H: | 2 c_1 = 2 c_3 O: | 4 c_1 = 4 c_4 S: | c_1 = c_4 Ba: | c_2 = c_4 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_1 = 1 and solve the system of equations for the remaining coefficients: c_1 = 1 c_2 = 1 c_3 = 1 c_4 = 1 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | H_2SO_4 + Ba ⟶ H_2 + BaSO_4

Structures

 + ⟶ +
+ ⟶ +

Names

sulfuric acid + barium ⟶ hydrogen + barium sulfate
sulfuric acid + barium ⟶ hydrogen + barium sulfate

Reaction thermodynamics

Enthalpy

 | sulfuric acid | barium | hydrogen | barium sulfate molecular enthalpy | -814 kJ/mol | 0 kJ/mol | 0 kJ/mol | -1473 kJ/mol total enthalpy | -814 kJ/mol | 0 kJ/mol | 0 kJ/mol | -1473 kJ/mol  | H_initial = -814 kJ/mol | | H_final = -1473 kJ/mol |  ΔH_rxn^0 | -1473 kJ/mol - -814 kJ/mol = -659.2 kJ/mol (exothermic) | | |
| sulfuric acid | barium | hydrogen | barium sulfate molecular enthalpy | -814 kJ/mol | 0 kJ/mol | 0 kJ/mol | -1473 kJ/mol total enthalpy | -814 kJ/mol | 0 kJ/mol | 0 kJ/mol | -1473 kJ/mol | H_initial = -814 kJ/mol | | H_final = -1473 kJ/mol | ΔH_rxn^0 | -1473 kJ/mol - -814 kJ/mol = -659.2 kJ/mol (exothermic) | | |

Entropy

 | sulfuric acid | barium | hydrogen | barium sulfate molecular entropy | 157 J/(mol K) | 67 J/(mol K) | 115 J/(mol K) | 132 J/(mol K) total entropy | 157 J/(mol K) | 67 J/(mol K) | 115 J/(mol K) | 132 J/(mol K)  | S_initial = 224 J/(mol K) | | S_final = 247 J/(mol K) |  ΔS_rxn^0 | 247 J/(mol K) - 224 J/(mol K) = 23 J/(mol K) (endoentropic) | | |
| sulfuric acid | barium | hydrogen | barium sulfate molecular entropy | 157 J/(mol K) | 67 J/(mol K) | 115 J/(mol K) | 132 J/(mol K) total entropy | 157 J/(mol K) | 67 J/(mol K) | 115 J/(mol K) | 132 J/(mol K) | S_initial = 224 J/(mol K) | | S_final = 247 J/(mol K) | ΔS_rxn^0 | 247 J/(mol K) - 224 J/(mol K) = 23 J/(mol K) (endoentropic) | | |

Equilibrium constant

Construct the equilibrium constant, K, expression for: H_2SO_4 + Ba ⟶ H_2 + BaSO_4 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the activity expression for each chemical species. • Use the activity expressions to build the equilibrium constant expression. Write the balanced chemical equation: H_2SO_4 + Ba ⟶ H_2 + BaSO_4 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i H_2SO_4 | 1 | -1 Ba | 1 | -1 H_2 | 1 | 1 BaSO_4 | 1 | 1 Assemble the activity expressions accounting for the state of matter and ν_i: chemical species | c_i | ν_i | activity expression H_2SO_4 | 1 | -1 | ([H2SO4])^(-1) Ba | 1 | -1 | ([Ba])^(-1) H_2 | 1 | 1 | [H2] BaSO_4 | 1 | 1 | [BaSO4] The equilibrium constant symbol in the concentration basis is: K_c Mulitply the activity expressions to arrive at the K_c expression: Answer: |   | K_c = ([H2SO4])^(-1) ([Ba])^(-1) [H2] [BaSO4] = ([H2] [BaSO4])/([H2SO4] [Ba])
Construct the equilibrium constant, K, expression for: H_2SO_4 + Ba ⟶ H_2 + BaSO_4 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the activity expression for each chemical species. • Use the activity expressions to build the equilibrium constant expression. Write the balanced chemical equation: H_2SO_4 + Ba ⟶ H_2 + BaSO_4 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i H_2SO_4 | 1 | -1 Ba | 1 | -1 H_2 | 1 | 1 BaSO_4 | 1 | 1 Assemble the activity expressions accounting for the state of matter and ν_i: chemical species | c_i | ν_i | activity expression H_2SO_4 | 1 | -1 | ([H2SO4])^(-1) Ba | 1 | -1 | ([Ba])^(-1) H_2 | 1 | 1 | [H2] BaSO_4 | 1 | 1 | [BaSO4] The equilibrium constant symbol in the concentration basis is: K_c Mulitply the activity expressions to arrive at the K_c expression: Answer: | | K_c = ([H2SO4])^(-1) ([Ba])^(-1) [H2] [BaSO4] = ([H2] [BaSO4])/([H2SO4] [Ba])

Rate of reaction

Construct the rate of reaction expression for: H_2SO_4 + Ba ⟶ H_2 + BaSO_4 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the rate term for each chemical species. • Write the rate of reaction expression. Write the balanced chemical equation: H_2SO_4 + Ba ⟶ H_2 + BaSO_4 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i H_2SO_4 | 1 | -1 Ba | 1 | -1 H_2 | 1 | 1 BaSO_4 | 1 | 1 The rate term for each chemical species, B_i, is 1/ν_i(Δ[B_i])/(Δt) where [B_i] is the amount concentration and t is time: chemical species | c_i | ν_i | rate term H_2SO_4 | 1 | -1 | -(Δ[H2SO4])/(Δt) Ba | 1 | -1 | -(Δ[Ba])/(Δt) H_2 | 1 | 1 | (Δ[H2])/(Δt) BaSO_4 | 1 | 1 | (Δ[BaSO4])/(Δt) (for infinitesimal rate of change, replace Δ with d) Set the rate terms equal to each other to arrive at the rate expression: Answer: |   | rate = -(Δ[H2SO4])/(Δt) = -(Δ[Ba])/(Δt) = (Δ[H2])/(Δt) = (Δ[BaSO4])/(Δt) (assuming constant volume and no accumulation of intermediates or side products)
Construct the rate of reaction expression for: H_2SO_4 + Ba ⟶ H_2 + BaSO_4 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the rate term for each chemical species. • Write the rate of reaction expression. Write the balanced chemical equation: H_2SO_4 + Ba ⟶ H_2 + BaSO_4 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i H_2SO_4 | 1 | -1 Ba | 1 | -1 H_2 | 1 | 1 BaSO_4 | 1 | 1 The rate term for each chemical species, B_i, is 1/ν_i(Δ[B_i])/(Δt) where [B_i] is the amount concentration and t is time: chemical species | c_i | ν_i | rate term H_2SO_4 | 1 | -1 | -(Δ[H2SO4])/(Δt) Ba | 1 | -1 | -(Δ[Ba])/(Δt) H_2 | 1 | 1 | (Δ[H2])/(Δt) BaSO_4 | 1 | 1 | (Δ[BaSO4])/(Δt) (for infinitesimal rate of change, replace Δ with d) Set the rate terms equal to each other to arrive at the rate expression: Answer: | | rate = -(Δ[H2SO4])/(Δt) = -(Δ[Ba])/(Δt) = (Δ[H2])/(Δt) = (Δ[BaSO4])/(Δt) (assuming constant volume and no accumulation of intermediates or side products)

Chemical names and formulas

 | sulfuric acid | barium | hydrogen | barium sulfate formula | H_2SO_4 | Ba | H_2 | BaSO_4 Hill formula | H_2O_4S | Ba | H_2 | BaO_4S name | sulfuric acid | barium | hydrogen | barium sulfate IUPAC name | sulfuric acid | barium | molecular hydrogen | barium(+2) cation sulfate
| sulfuric acid | barium | hydrogen | barium sulfate formula | H_2SO_4 | Ba | H_2 | BaSO_4 Hill formula | H_2O_4S | Ba | H_2 | BaO_4S name | sulfuric acid | barium | hydrogen | barium sulfate IUPAC name | sulfuric acid | barium | molecular hydrogen | barium(+2) cation sulfate

Substance properties

 | sulfuric acid | barium | hydrogen | barium sulfate molar mass | 98.07 g/mol | 137.327 g/mol | 2.016 g/mol | 233.38 g/mol phase | liquid (at STP) | solid (at STP) | gas (at STP) | solid (at STP) melting point | 10.371 °C | 725 °C | -259.2 °C | 1345 °C boiling point | 279.6 °C | 1640 °C | -252.8 °C |  density | 1.8305 g/cm^3 | 3.6 g/cm^3 | 8.99×10^-5 g/cm^3 (at 0 °C) | 4.5 g/cm^3 solubility in water | very soluble | insoluble | | insoluble surface tension | 0.0735 N/m | 0.224 N/m | |  dynamic viscosity | 0.021 Pa s (at 25 °C) | | 8.9×10^-6 Pa s (at 25 °C) |  odor | odorless | | odorless |
| sulfuric acid | barium | hydrogen | barium sulfate molar mass | 98.07 g/mol | 137.327 g/mol | 2.016 g/mol | 233.38 g/mol phase | liquid (at STP) | solid (at STP) | gas (at STP) | solid (at STP) melting point | 10.371 °C | 725 °C | -259.2 °C | 1345 °C boiling point | 279.6 °C | 1640 °C | -252.8 °C | density | 1.8305 g/cm^3 | 3.6 g/cm^3 | 8.99×10^-5 g/cm^3 (at 0 °C) | 4.5 g/cm^3 solubility in water | very soluble | insoluble | | insoluble surface tension | 0.0735 N/m | 0.224 N/m | | dynamic viscosity | 0.021 Pa s (at 25 °C) | | 8.9×10^-6 Pa s (at 25 °C) | odor | odorless | | odorless |

Units