HClKOH = KClH2O

HClKOH ⟶ KClH2O

Balance the chemical equation algebraically: HClKOH ⟶ KClH2O Add stoichiometric coefficients, c_i, to the reactants and products: c_1 HClKOH ⟶ c_2 KClH2O Set the number of atoms in the reactants equal to the number of atoms in the products for H, Cl, K and O: H: | 2 c_1 = 2 c_2 Cl: | c_1 = c_2 K: | c_1 = c_2 O: | c_1 = c_2 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_1 = 1 and solve the system of equations for the remaining coefficients: c_1 = 1 c_2 = 1 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | HClKOH ⟶ KClH2O

HClKOH ⟶ KClH2O

HClKOH ⟶ KClH2O

Construct the equilibrium constant, K, expression for: HClKOH ⟶ KClH2O Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the activity expression for each chemical species. • Use the activity expressions to build the equilibrium constant expression. Write the balanced chemical equation: HClKOH ⟶ KClH2O Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i HClKOH | 1 | -1 KClH2O | 1 | 1 Assemble the activity expressions accounting for the state of matter and ν_i: chemical species | c_i | ν_i | activity expression HClKOH | 1 | -1 | ([HClKOH])^(-1) KClH2O | 1 | 1 | [KClH2O] The equilibrium constant symbol in the concentration basis is: K_c Mulitply the activity expressions to arrive at the K_c expression: Answer: | | K_c = ([HClKOH])^(-1) [KClH2O] = ([KClH2O])/([HClKOH])

Construct the rate of reaction expression for: HClKOH ⟶ KClH2O Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the rate term for each chemical species. • Write the rate of reaction expression. Write the balanced chemical equation: HClKOH ⟶ KClH2O Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i HClKOH | 1 | -1 KClH2O | 1 | 1 The rate term for each chemical species, B_i, is 1/ν_i(Δ[B_i])/(Δt) where [B_i] is the amount concentration and t is time: chemical species | c_i | ν_i | rate term HClKOH | 1 | -1 | -(Δ[HClKOH])/(Δt) KClH2O | 1 | 1 | (Δ[KClH2O])/(Δt) (for infinitesimal rate of change, replace Δ with d) Set the rate terms equal to each other to arrive at the rate expression: Answer: | | rate = -(Δ[HClKOH])/(Δt) = (Δ[KClH2O])/(Δt) (assuming constant volume and no accumulation of intermediates or side products)

| HClKOH | KClH2O formula | HClKOH | KClH2O Hill formula | H2ClKO | H2ClKO

| HClKOH | KClH2O molar mass | 92.56 g/mol | 92.56 g/mol