Input interpretation
(S)-(+)-2-fluoro-α-methyl-4-biphenylacetic acid | molar mass
Result
Find the molar mass, M, for (S)-(+)-2-fluoro-α-methyl-4-biphenylacetic acid: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: C_6H_5C_6H_3(F)CH(CH_3)CO_2H Use the chemical formula, C_6H_5C_6H_3(F)CH(CH_3)CO_2H, to count the number of atoms, N_i, for each element: | N_i C (carbon) | 15 F (fluorine) | 1 H (hydrogen) | 13 O (oxygen) | 2 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) C (carbon) | 15 | 12.011 F (fluorine) | 1 | 18.998403163 H (hydrogen) | 13 | 1.008 O (oxygen) | 2 | 15.999 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) C (carbon) | 15 | 12.011 | 15 × 12.011 = 180.165 F (fluorine) | 1 | 18.998403163 | 1 × 18.998403163 = 18.998403163 H (hydrogen) | 13 | 1.008 | 13 × 1.008 = 13.104 O (oxygen) | 2 | 15.999 | 2 × 15.999 = 31.998 M = 180.165 g/mol + 18.998403163 g/mol + 13.104 g/mol + 31.998 g/mol = 244.265 g/mol
Unit conversion
0.24427 kg/mol (kilograms per mole)
Comparisons
≈ 0.34 × molar mass of fullerene ( ≈ 721 g/mol )
≈ 1.3 × molar mass of caffeine ( ≈ 194 g/mol )
≈ 4.2 × molar mass of sodium chloride ( ≈ 58 g/mol )
Corresponding quantities
Mass of a molecule m from m = M/N_A: | 4.1×10^-22 grams | 4.1×10^-25 kg (kilograms) | 244 u (unified atomic mass units) | 244 Da (daltons)
Relative molecular mass M_r from M_r = M_u/M: | 244