Input interpretation
![boric acid | molar mass](../image_source/befa9120525c7bc65e19acf3073ca3e9.png)
boric acid | molar mass
Result
![Find the molar mass, M, for boric acid: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: B(OH)_3 Use the chemical formula to count the number of atoms, N_i, for each element: | N_i B (boron) | 1 H (hydrogen) | 3 O (oxygen) | 3 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) B (boron) | 1 | 10.81 H (hydrogen) | 3 | 1.008 O (oxygen) | 3 | 15.999 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) B (boron) | 1 | 10.81 | 1 × 10.81 = 10.81 H (hydrogen) | 3 | 1.008 | 3 × 1.008 = 3.024 O (oxygen) | 3 | 15.999 | 3 × 15.999 = 47.997 M = 10.81 g/mol + 3.024 g/mol + 47.997 g/mol = 61.83 g/mol](../image_source/7e31303477bdaf10d7956dec79369b9e.png)
Find the molar mass, M, for boric acid: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: B(OH)_3 Use the chemical formula to count the number of atoms, N_i, for each element: | N_i B (boron) | 1 H (hydrogen) | 3 O (oxygen) | 3 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) B (boron) | 1 | 10.81 H (hydrogen) | 3 | 1.008 O (oxygen) | 3 | 15.999 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) B (boron) | 1 | 10.81 | 1 × 10.81 = 10.81 H (hydrogen) | 3 | 1.008 | 3 × 1.008 = 3.024 O (oxygen) | 3 | 15.999 | 3 × 15.999 = 47.997 M = 10.81 g/mol + 3.024 g/mol + 47.997 g/mol = 61.83 g/mol
Unit conversion
![0.06183 kg/mol (kilograms per mole)](../image_source/468d6bd80381945d46c7a04ad3d79ca8.png)
0.06183 kg/mol (kilograms per mole)
Comparisons
![≈ ( 0.086 ≈ 1/12 ) × molar mass of fullerene ( ≈ 721 g/mol )](../image_source/041d4f344fe8b71cfed2c0113bf7531b.png)
≈ ( 0.086 ≈ 1/12 ) × molar mass of fullerene ( ≈ 721 g/mol )
![≈ 0.32 × molar mass of caffeine ( ≈ 194 g/mol )](../image_source/080c0bd5fc1265ff43e69730261c01e1.png)
≈ 0.32 × molar mass of caffeine ( ≈ 194 g/mol )
![≈ 1.1 × molar mass of sodium chloride ( ≈ 58 g/mol )](../image_source/9964519558394633a3aa3967a37ec5e6.png)
≈ 1.1 × molar mass of sodium chloride ( ≈ 58 g/mol )
Corresponding quantities
![Mass of a molecule m from m = M/N_A: | 1×10^-22 grams | 1×10^-25 kg (kilograms) | 62 u (unified atomic mass units) | 62 Da (daltons)](../image_source/44eb42a1754a92a182dae3e6462adaa0.png)
Mass of a molecule m from m = M/N_A: | 1×10^-22 grams | 1×10^-25 kg (kilograms) | 62 u (unified atomic mass units) | 62 Da (daltons)
![Relative molecular mass M_r from M_r = M_u/M: | 62](../image_source/ad6121d02a9282fe16ca9ee32a2b883e.png)
Relative molecular mass M_r from M_r = M_u/M: | 62