Search

KOH + KCr(SO4)2 = K2SO4 + Cr(OH)3

Input interpretation

KOH potassium hydroxide + CrKO_8S_2 chrome potash alum ⟶ K_2SO_4 potassium sulfate + Cr(OH)3
KOH potassium hydroxide + CrKO_8S_2 chrome potash alum ⟶ K_2SO_4 potassium sulfate + Cr(OH)3

Balanced equation

Balance the chemical equation algebraically: KOH + CrKO_8S_2 ⟶ K_2SO_4 + Cr(OH)3 Add stoichiometric coefficients, c_i, to the reactants and products: c_1 KOH + c_2 CrKO_8S_2 ⟶ c_3 K_2SO_4 + c_4 Cr(OH)3 Set the number of atoms in the reactants equal to the number of atoms in the products for H, K, O, Cr and S: H: | c_1 = 3 c_4 K: | c_1 + c_2 = 2 c_3 O: | c_1 + 8 c_2 = 4 c_3 + 3 c_4 Cr: | c_2 = c_4 S: | 2 c_2 = c_3 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_2 = 1 and solve the system of equations for the remaining coefficients: c_1 = 3 c_2 = 1 c_3 = 2 c_4 = 1 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | 3 KOH + CrKO_8S_2 ⟶ 2 K_2SO_4 + Cr(OH)3
Balance the chemical equation algebraically: KOH + CrKO_8S_2 ⟶ K_2SO_4 + Cr(OH)3 Add stoichiometric coefficients, c_i, to the reactants and products: c_1 KOH + c_2 CrKO_8S_2 ⟶ c_3 K_2SO_4 + c_4 Cr(OH)3 Set the number of atoms in the reactants equal to the number of atoms in the products for H, K, O, Cr and S: H: | c_1 = 3 c_4 K: | c_1 + c_2 = 2 c_3 O: | c_1 + 8 c_2 = 4 c_3 + 3 c_4 Cr: | c_2 = c_4 S: | 2 c_2 = c_3 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_2 = 1 and solve the system of equations for the remaining coefficients: c_1 = 3 c_2 = 1 c_3 = 2 c_4 = 1 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | 3 KOH + CrKO_8S_2 ⟶ 2 K_2SO_4 + Cr(OH)3

Structures

+ ⟶ + Cr(OH)3
+ ⟶ + Cr(OH)3

Names

potassium hydroxide + chrome potash alum ⟶ potassium sulfate + Cr(OH)3
potassium hydroxide + chrome potash alum ⟶ potassium sulfate + Cr(OH)3

Equilibrium constant

Construct the equilibrium constant, K, expression for: KOH + CrKO_8S_2 ⟶ K_2SO_4 + Cr(OH)3 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the activity expression for each chemical species. • Use the activity expressions to build the equilibrium constant expression. Write the balanced chemical equation: 3 KOH + CrKO_8S_2 ⟶ 2 K_2SO_4 + Cr(OH)3 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i KOH | 3 | -3 CrKO_8S_2 | 1 | -1 K_2SO_4 | 2 | 2 Cr(OH)3 | 1 | 1 Assemble the activity expressions accounting for the state of matter and ν_i: chemical species | c_i | ν_i | activity expression KOH | 3 | -3 | ([KOH])^(-3) CrKO_8S_2 | 1 | -1 | ([CrKO8S2])^(-1) K_2SO_4 | 2 | 2 | ([K2SO4])^2 Cr(OH)3 | 1 | 1 | [Cr(OH)3] The equilibrium constant symbol in the concentration basis is: K_c Mulitply the activity expressions to arrive at the K_c expression: Answer: | | K_c = ([KOH])^(-3) ([CrKO8S2])^(-1) ([K2SO4])^2 [Cr(OH)3] = (([K2SO4])^2 [Cr(OH)3])/(([KOH])^3 [CrKO8S2])
Construct the equilibrium constant, K, expression for: KOH + CrKO_8S_2 ⟶ K_2SO_4 + Cr(OH)3 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the activity expression for each chemical species. • Use the activity expressions to build the equilibrium constant expression. Write the balanced chemical equation: 3 KOH + CrKO_8S_2 ⟶ 2 K_2SO_4 + Cr(OH)3 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i KOH | 3 | -3 CrKO_8S_2 | 1 | -1 K_2SO_4 | 2 | 2 Cr(OH)3 | 1 | 1 Assemble the activity expressions accounting for the state of matter and ν_i: chemical species | c_i | ν_i | activity expression KOH | 3 | -3 | ([KOH])^(-3) CrKO_8S_2 | 1 | -1 | ([CrKO8S2])^(-1) K_2SO_4 | 2 | 2 | ([K2SO4])^2 Cr(OH)3 | 1 | 1 | [Cr(OH)3] The equilibrium constant symbol in the concentration basis is: K_c Mulitply the activity expressions to arrive at the K_c expression: Answer: | | K_c = ([KOH])^(-3) ([CrKO8S2])^(-1) ([K2SO4])^2 [Cr(OH)3] = (([K2SO4])^2 [Cr(OH)3])/(([KOH])^3 [CrKO8S2])

Rate of reaction

Construct the rate of reaction expression for: KOH + CrKO_8S_2 ⟶ K_2SO_4 + Cr(OH)3 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the rate term for each chemical species. • Write the rate of reaction expression. Write the balanced chemical equation: 3 KOH + CrKO_8S_2 ⟶ 2 K_2SO_4 + Cr(OH)3 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i KOH | 3 | -3 CrKO_8S_2 | 1 | -1 K_2SO_4 | 2 | 2 Cr(OH)3 | 1 | 1 The rate term for each chemical species, B_i, is 1/ν_i(Δ[B_i])/(Δt) where [B_i] is the amount concentration and t is time: chemical species | c_i | ν_i | rate term KOH | 3 | -3 | -1/3 (Δ[KOH])/(Δt) CrKO_8S_2 | 1 | -1 | -(Δ[CrKO8S2])/(Δt) K_2SO_4 | 2 | 2 | 1/2 (Δ[K2SO4])/(Δt) Cr(OH)3 | 1 | 1 | (Δ[Cr(OH)3])/(Δt) (for infinitesimal rate of change, replace Δ with d) Set the rate terms equal to each other to arrive at the rate expression: Answer: | | rate = -1/3 (Δ[KOH])/(Δt) = -(Δ[CrKO8S2])/(Δt) = 1/2 (Δ[K2SO4])/(Δt) = (Δ[Cr(OH)3])/(Δt) (assuming constant volume and no accumulation of intermediates or side products)
Construct the rate of reaction expression for: KOH + CrKO_8S_2 ⟶ K_2SO_4 + Cr(OH)3 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the rate term for each chemical species. • Write the rate of reaction expression. Write the balanced chemical equation: 3 KOH + CrKO_8S_2 ⟶ 2 K_2SO_4 + Cr(OH)3 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i KOH | 3 | -3 CrKO_8S_2 | 1 | -1 K_2SO_4 | 2 | 2 Cr(OH)3 | 1 | 1 The rate term for each chemical species, B_i, is 1/ν_i(Δ[B_i])/(Δt) where [B_i] is the amount concentration and t is time: chemical species | c_i | ν_i | rate term KOH | 3 | -3 | -1/3 (Δ[KOH])/(Δt) CrKO_8S_2 | 1 | -1 | -(Δ[CrKO8S2])/(Δt) K_2SO_4 | 2 | 2 | 1/2 (Δ[K2SO4])/(Δt) Cr(OH)3 | 1 | 1 | (Δ[Cr(OH)3])/(Δt) (for infinitesimal rate of change, replace Δ with d) Set the rate terms equal to each other to arrive at the rate expression: Answer: | | rate = -1/3 (Δ[KOH])/(Δt) = -(Δ[CrKO8S2])/(Δt) = 1/2 (Δ[K2SO4])/(Δt) = (Δ[Cr(OH)3])/(Δt) (assuming constant volume and no accumulation of intermediates or side products)

Chemical names and formulas

| potassium hydroxide | chrome potash alum | potassium sulfate | Cr(OH)3 formula | KOH | CrKO_8S_2 | K_2SO_4 | Cr(OH)3 Hill formula | HKO | CrKO_8S_2 | K_2O_4S | H3CrO3 name | potassium hydroxide | chrome potash alum | potassium sulfate | IUPAC name | potassium hydroxide | potassium chromium(+3) cation disulfate | dipotassium sulfate |
| potassium hydroxide | chrome potash alum | potassium sulfate | Cr(OH)3 formula | KOH | CrKO_8S_2 | K_2SO_4 | Cr(OH)3 Hill formula | HKO | CrKO_8S_2 | K_2O_4S | H3CrO3 name | potassium hydroxide | chrome potash alum | potassium sulfate | IUPAC name | potassium hydroxide | potassium chromium(+3) cation disulfate | dipotassium sulfate |

Substance properties

| potassium hydroxide | chrome potash alum | potassium sulfate | Cr(OH)3 molar mass | 56.105 g/mol | 283.21 g/mol | 174.25 g/mol | 103.02 g/mol phase | solid (at STP) | solid (at STP) | | melting point | 406 °C | 89 °C | | boiling point | 1327 °C | 400 °C | | density | 2.044 g/cm^3 | 2.548 g/cm^3 | | solubility in water | soluble | insoluble | soluble | dynamic viscosity | 0.001 Pa s (at 550 °C) | | |
| potassium hydroxide | chrome potash alum | potassium sulfate | Cr(OH)3 molar mass | 56.105 g/mol | 283.21 g/mol | 174.25 g/mol | 103.02 g/mol phase | solid (at STP) | solid (at STP) | | melting point | 406 °C | 89 °C | | boiling point | 1327 °C | 400 °C | | density | 2.044 g/cm^3 | 2.548 g/cm^3 | | solubility in water | soluble | insoluble | soluble | dynamic viscosity | 0.001 Pa s (at 550 °C) | | |

Units

Random Queries

InChI identifier of L-lysine vs cobalt
melting point of chlorine trifluoride vs hydrogen
alternate names of oleum
molar mass of dithionite anion vs hypoiodite anion
discovery year of selenium
chemical functional groups of bromocresol green
PubChem SID number of barium sodium niobium oxide
Mohs hardness of rosickyite
element types of acetaminophen
formulas of cobalt(III) ions