Input interpretation
![n-acetyl-4-aminobutanal | molar mass](../image_source/09c3c15a641dc710789688ada45afba1.png)
n-acetyl-4-aminobutanal | molar mass
Result
![Find the molar mass, M, for n-acetyl-4-aminobutanal: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: C_6H_11N_1O_2 Use the chemical formula to count the number of atoms, N_i, for each element: | N_i C (carbon) | 6 H (hydrogen) | 11 N (nitrogen) | 1 O (oxygen) | 2 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) C (carbon) | 6 | 12.011 H (hydrogen) | 11 | 1.008 N (nitrogen) | 1 | 14.007 O (oxygen) | 2 | 15.999 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) C (carbon) | 6 | 12.011 | 6 × 12.011 = 72.066 H (hydrogen) | 11 | 1.008 | 11 × 1.008 = 11.088 N (nitrogen) | 1 | 14.007 | 1 × 14.007 = 14.007 O (oxygen) | 2 | 15.999 | 2 × 15.999 = 31.998 M = 72.066 g/mol + 11.088 g/mol + 14.007 g/mol + 31.998 g/mol = 129.159 g/mol](../image_source/2518b1d929b072060e510561d063ace3.png)
Find the molar mass, M, for n-acetyl-4-aminobutanal: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: C_6H_11N_1O_2 Use the chemical formula to count the number of atoms, N_i, for each element: | N_i C (carbon) | 6 H (hydrogen) | 11 N (nitrogen) | 1 O (oxygen) | 2 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) C (carbon) | 6 | 12.011 H (hydrogen) | 11 | 1.008 N (nitrogen) | 1 | 14.007 O (oxygen) | 2 | 15.999 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) C (carbon) | 6 | 12.011 | 6 × 12.011 = 72.066 H (hydrogen) | 11 | 1.008 | 11 × 1.008 = 11.088 N (nitrogen) | 1 | 14.007 | 1 × 14.007 = 14.007 O (oxygen) | 2 | 15.999 | 2 × 15.999 = 31.998 M = 72.066 g/mol + 11.088 g/mol + 14.007 g/mol + 31.998 g/mol = 129.159 g/mol
Unit conversion
![0.12916 kg/mol (kilograms per mole)](../image_source/4259f897b862b1c067fc1be31ff9056d.png)
0.12916 kg/mol (kilograms per mole)
Comparisons
![≈ ( 0.18 ≈ 1/6 ) × molar mass of fullerene ( ≈ 721 g/mol )](../image_source/b0fab53cf9841e634d57c436f0eebee9.png)
≈ ( 0.18 ≈ 1/6 ) × molar mass of fullerene ( ≈ 721 g/mol )
![≈ 0.67 × molar mass of caffeine ( ≈ 194 g/mol )](../image_source/55aa67bcfc97610bcbb5f9bf808152c4.png)
≈ 0.67 × molar mass of caffeine ( ≈ 194 g/mol )
![≈ 2.2 × molar mass of sodium chloride ( ≈ 58 g/mol )](../image_source/7572ee46c5c3b433ed9c111c75b061b8.png)
≈ 2.2 × molar mass of sodium chloride ( ≈ 58 g/mol )
Corresponding quantities
![Mass of a molecule m from m = M/N_A: | 2.1×10^-22 grams | 2.1×10^-25 kg (kilograms) | 129 u (unified atomic mass units) | 129 Da (daltons)](../image_source/738bb10832655b23a685b7775985f386.png)
Mass of a molecule m from m = M/N_A: | 2.1×10^-22 grams | 2.1×10^-25 kg (kilograms) | 129 u (unified atomic mass units) | 129 Da (daltons)
![Relative molecular mass M_r from M_r = M_u/M: | 129](../image_source/9827b029f2c40b73015985afa24b114a.png)
Relative molecular mass M_r from M_r = M_u/M: | 129