Input interpretation
![aluminum cerium oxide | molar mass](../image_source/8d449d9837e3391cd5ea0912bfe02ef4.png)
aluminum cerium oxide | molar mass
Result
![Find the molar mass, M, for aluminum cerium oxide: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: AlCeO_3 Use the chemical formula to count the number of atoms, N_i, for each element: | N_i Al (aluminum) | 1 Ce (cerium) | 1 O (oxygen) | 3 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) Al (aluminum) | 1 | 26.9815385 Ce (cerium) | 1 | 140.116 O (oxygen) | 3 | 15.999 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) Al (aluminum) | 1 | 26.9815385 | 1 × 26.9815385 = 26.9815385 Ce (cerium) | 1 | 140.116 | 1 × 140.116 = 140.116 O (oxygen) | 3 | 15.999 | 3 × 15.999 = 47.997 M = 26.9815385 g/mol + 140.116 g/mol + 47.997 g/mol = 215.095 g/mol](../image_source/91bb9ea08d7367f477338747236fc121.png)
Find the molar mass, M, for aluminum cerium oxide: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: AlCeO_3 Use the chemical formula to count the number of atoms, N_i, for each element: | N_i Al (aluminum) | 1 Ce (cerium) | 1 O (oxygen) | 3 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) Al (aluminum) | 1 | 26.9815385 Ce (cerium) | 1 | 140.116 O (oxygen) | 3 | 15.999 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) Al (aluminum) | 1 | 26.9815385 | 1 × 26.9815385 = 26.9815385 Ce (cerium) | 1 | 140.116 | 1 × 140.116 = 140.116 O (oxygen) | 3 | 15.999 | 3 × 15.999 = 47.997 M = 26.9815385 g/mol + 140.116 g/mol + 47.997 g/mol = 215.095 g/mol
Unit conversion
![0.215095 kg/mol (kilograms per mole)](../image_source/725197d3dc3e0670ed30de3ce782473c.png)
0.215095 kg/mol (kilograms per mole)
Comparisons
![≈ 0.3 × molar mass of fullerene ( ≈ 721 g/mol )](../image_source/a81ec1fee9e30e91679155f70ac3d503.png)
≈ 0.3 × molar mass of fullerene ( ≈ 721 g/mol )
![≈ 1.1 × molar mass of caffeine ( ≈ 194 g/mol )](../image_source/6ac5601306a5e0c5f081516c7d9f0835.png)
≈ 1.1 × molar mass of caffeine ( ≈ 194 g/mol )
![≈ 3.7 × molar mass of sodium chloride ( ≈ 58 g/mol )](../image_source/04976c9df1890dbe70b9a260cad3c599.png)
≈ 3.7 × molar mass of sodium chloride ( ≈ 58 g/mol )
Corresponding quantities
![Mass of a molecule m from m = M/N_A: | 3.6×10^-22 grams | 3.6×10^-25 kg (kilograms) | 215 u (unified atomic mass units) | 215 Da (daltons)](../image_source/313d858c76b644137f9d1536d98247cf.png)
Mass of a molecule m from m = M/N_A: | 3.6×10^-22 grams | 3.6×10^-25 kg (kilograms) | 215 u (unified atomic mass units) | 215 Da (daltons)
![Relative molecular mass M_r from M_r = M_u/M: | 215](../image_source/04ee24fd74d1cd563b19dea3ab24d729.png)
Relative molecular mass M_r from M_r = M_u/M: | 215