Input interpretation
![sulfuric acid + potassium permanganate + formaldehyde ⟶ water + carbon dioxide + potassium sulfate + manganese(II) sulfate](../image_source/9e393b723565c55d0dc9a08b15670ffd.png)
sulfuric acid + potassium permanganate + formaldehyde ⟶ water + carbon dioxide + potassium sulfate + manganese(II) sulfate
Balanced equation
![Balance the chemical equation algebraically: + + ⟶ + + + Add stoichiometric coefficients, c_i, to the reactants and products: c_1 + c_2 + c_3 ⟶ c_4 + c_5 + c_6 + c_7 Set the number of atoms in the reactants equal to the number of atoms in the products for H, O, S, K, Mn and C: H: | 2 c_1 + 2 c_3 = 2 c_4 O: | 4 c_1 + 4 c_2 + c_3 = c_4 + 2 c_5 + 4 c_6 + 4 c_7 S: | c_1 = c_6 + c_7 K: | c_2 = 2 c_6 Mn: | c_2 = c_7 C: | c_3 = c_5 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_6 = 1 and solve the system of equations for the remaining coefficients: c_1 = 3 c_2 = 2 c_3 = 5/2 c_4 = 11/2 c_5 = 5/2 c_6 = 1 c_7 = 2 Multiply by the least common denominator, 2, to eliminate fractional coefficients: c_1 = 6 c_2 = 4 c_3 = 5 c_4 = 11 c_5 = 5 c_6 = 2 c_7 = 4 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | 6 + 4 + 5 ⟶ 11 + 5 + 2 + 4](../image_source/500ca2af207d06797479bba38b386453.png)
Balance the chemical equation algebraically: + + ⟶ + + + Add stoichiometric coefficients, c_i, to the reactants and products: c_1 + c_2 + c_3 ⟶ c_4 + c_5 + c_6 + c_7 Set the number of atoms in the reactants equal to the number of atoms in the products for H, O, S, K, Mn and C: H: | 2 c_1 + 2 c_3 = 2 c_4 O: | 4 c_1 + 4 c_2 + c_3 = c_4 + 2 c_5 + 4 c_6 + 4 c_7 S: | c_1 = c_6 + c_7 K: | c_2 = 2 c_6 Mn: | c_2 = c_7 C: | c_3 = c_5 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_6 = 1 and solve the system of equations for the remaining coefficients: c_1 = 3 c_2 = 2 c_3 = 5/2 c_4 = 11/2 c_5 = 5/2 c_6 = 1 c_7 = 2 Multiply by the least common denominator, 2, to eliminate fractional coefficients: c_1 = 6 c_2 = 4 c_3 = 5 c_4 = 11 c_5 = 5 c_6 = 2 c_7 = 4 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | 6 + 4 + 5 ⟶ 11 + 5 + 2 + 4
Structures
![+ + ⟶ + + +](../image_source/dea37357083da402746a36c234f1fdac.png)
+ + ⟶ + + +
Names
![sulfuric acid + potassium permanganate + formaldehyde ⟶ water + carbon dioxide + potassium sulfate + manganese(II) sulfate](../image_source/04def55a8080dd3c1835c59f52c8c0ad.png)
sulfuric acid + potassium permanganate + formaldehyde ⟶ water + carbon dioxide + potassium sulfate + manganese(II) sulfate
Chemical names and formulas
![| sulfuric acid | potassium permanganate | formaldehyde | water | carbon dioxide | potassium sulfate | manganese(II) sulfate Hill formula | H_2O_4S | KMnO_4 | CH_2O | H_2O | CO_2 | K_2O_4S | MnO_4S name | sulfuric acid | potassium permanganate | formaldehyde | water | carbon dioxide | potassium sulfate | manganese(II) sulfate IUPAC name | sulfuric acid | potassium permanganate | formaldehyde | water | carbon dioxide | dipotassium sulfate | manganese(+2) cation sulfate](../image_source/0386b8f52e271e62cc81184b9fd99ecd.png)
| sulfuric acid | potassium permanganate | formaldehyde | water | carbon dioxide | potassium sulfate | manganese(II) sulfate Hill formula | H_2O_4S | KMnO_4 | CH_2O | H_2O | CO_2 | K_2O_4S | MnO_4S name | sulfuric acid | potassium permanganate | formaldehyde | water | carbon dioxide | potassium sulfate | manganese(II) sulfate IUPAC name | sulfuric acid | potassium permanganate | formaldehyde | water | carbon dioxide | dipotassium sulfate | manganese(+2) cation sulfate