Input interpretation
![zirconium(IV) carbide | molar mass](../image_source/9254a04ba4cb46b922300702a7de0780.png)
zirconium(IV) carbide | molar mass
Result
![Find the molar mass, M, for zirconium(IV) carbide: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: ZrC Use the chemical formula, ZrC, to count the number of atoms, N_i, for each element: | N_i C (carbon) | 1 H (hydrogen) | 1 Zr (zirconium) | 1 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) C (carbon) | 1 | 12.011 H (hydrogen) | 1 | 1.008 Zr (zirconium) | 1 | 91.224 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) C (carbon) | 1 | 12.011 | 1 × 12.011 = 12.011 H (hydrogen) | 1 | 1.008 | 1 × 1.008 = 1.008 Zr (zirconium) | 1 | 91.224 | 1 × 91.224 = 91.224 M = 12.011 g/mol + 1.008 g/mol + 91.224 g/mol = 104.243 g/mol](../image_source/4d4ffdc73aa89a815d7fba2bd3d20d75.png)
Find the molar mass, M, for zirconium(IV) carbide: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: ZrC Use the chemical formula, ZrC, to count the number of atoms, N_i, for each element: | N_i C (carbon) | 1 H (hydrogen) | 1 Zr (zirconium) | 1 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) C (carbon) | 1 | 12.011 H (hydrogen) | 1 | 1.008 Zr (zirconium) | 1 | 91.224 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) C (carbon) | 1 | 12.011 | 1 × 12.011 = 12.011 H (hydrogen) | 1 | 1.008 | 1 × 1.008 = 1.008 Zr (zirconium) | 1 | 91.224 | 1 × 91.224 = 91.224 M = 12.011 g/mol + 1.008 g/mol + 91.224 g/mol = 104.243 g/mol
Unit conversion
![0.10424 kg/mol (kilograms per mole)](../image_source/95e77bc8f6dc5c2f7bbaccabcc86ce88.png)
0.10424 kg/mol (kilograms per mole)
Comparisons
![≈ ( 0.14 ≈ 1/7 ) × molar mass of fullerene ( ≈ 721 g/mol )](../image_source/b83fdc2203d4832625d81fb71e4556eb.png)
≈ ( 0.14 ≈ 1/7 ) × molar mass of fullerene ( ≈ 721 g/mol )
![≈ 0.54 × molar mass of caffeine ( ≈ 194 g/mol )](../image_source/15536c79649ffa146ccc0929fc888ba8.png)
≈ 0.54 × molar mass of caffeine ( ≈ 194 g/mol )
![≈ 1.8 × molar mass of sodium chloride ( ≈ 58 g/mol )](../image_source/5a96703daf010a593a0f022d891f126b.png)
≈ 1.8 × molar mass of sodium chloride ( ≈ 58 g/mol )
Corresponding quantities
![Mass of a molecule m from m = M/N_A: | 1.7×10^-22 grams | 1.7×10^-25 kg (kilograms) | 104 u (unified atomic mass units) | 104 Da (daltons)](../image_source/8bfe8838b7710543af759baca19c9bb6.png)
Mass of a molecule m from m = M/N_A: | 1.7×10^-22 grams | 1.7×10^-25 kg (kilograms) | 104 u (unified atomic mass units) | 104 Da (daltons)
![Relative molecular mass M_r from M_r = M_u/M: | 104](../image_source/30358ae84ad2ffc736a8a016e42d01ce.png)
Relative molecular mass M_r from M_r = M_u/M: | 104