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H2SO4 + NH4Cl = HCl + (NH4)2SO4

Input interpretation

H_2SO_4 sulfuric acid + NH_4Cl ammonium chloride ⟶ HCl hydrogen chloride + (NH_4)_2SO_4 ammonium sulfate
H_2SO_4 sulfuric acid + NH_4Cl ammonium chloride ⟶ HCl hydrogen chloride + (NH_4)_2SO_4 ammonium sulfate

Balanced equation

Balance the chemical equation algebraically: H_2SO_4 + NH_4Cl ⟶ HCl + (NH_4)_2SO_4 Add stoichiometric coefficients, c_i, to the reactants and products: c_1 H_2SO_4 + c_2 NH_4Cl ⟶ c_3 HCl + c_4 (NH_4)_2SO_4 Set the number of atoms in the reactants equal to the number of atoms in the products for H, O, S, Cl and N: H: | 2 c_1 + 4 c_2 = c_3 + 8 c_4 O: | 4 c_1 = 4 c_4 S: | c_1 = c_4 Cl: | c_2 = c_3 N: | c_2 = 2 c_4 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_1 = 1 and solve the system of equations for the remaining coefficients: c_1 = 1 c_2 = 2 c_3 = 2 c_4 = 1 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: |   | H_2SO_4 + 2 NH_4Cl ⟶ 2 HCl + (NH_4)_2SO_4
Balance the chemical equation algebraically: H_2SO_4 + NH_4Cl ⟶ HCl + (NH_4)_2SO_4 Add stoichiometric coefficients, c_i, to the reactants and products: c_1 H_2SO_4 + c_2 NH_4Cl ⟶ c_3 HCl + c_4 (NH_4)_2SO_4 Set the number of atoms in the reactants equal to the number of atoms in the products for H, O, S, Cl and N: H: | 2 c_1 + 4 c_2 = c_3 + 8 c_4 O: | 4 c_1 = 4 c_4 S: | c_1 = c_4 Cl: | c_2 = c_3 N: | c_2 = 2 c_4 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_1 = 1 and solve the system of equations for the remaining coefficients: c_1 = 1 c_2 = 2 c_3 = 2 c_4 = 1 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | H_2SO_4 + 2 NH_4Cl ⟶ 2 HCl + (NH_4)_2SO_4

Structures

 + ⟶ +
+ ⟶ +

Names

sulfuric acid + ammonium chloride ⟶ hydrogen chloride + ammonium sulfate
sulfuric acid + ammonium chloride ⟶ hydrogen chloride + ammonium sulfate

Reaction thermodynamics

Enthalpy

 | sulfuric acid | ammonium chloride | hydrogen chloride | ammonium sulfate molecular enthalpy | -814 kJ/mol | -314.4 kJ/mol | -92.3 kJ/mol | -1181 kJ/mol total enthalpy | -814 kJ/mol | -628.8 kJ/mol | -184.6 kJ/mol | -1181 kJ/mol  | H_initial = -1443 kJ/mol | | H_final = -1366 kJ/mol |  ΔH_rxn^0 | -1366 kJ/mol - -1443 kJ/mol = 77.3 kJ/mol (endothermic) | | |
| sulfuric acid | ammonium chloride | hydrogen chloride | ammonium sulfate molecular enthalpy | -814 kJ/mol | -314.4 kJ/mol | -92.3 kJ/mol | -1181 kJ/mol total enthalpy | -814 kJ/mol | -628.8 kJ/mol | -184.6 kJ/mol | -1181 kJ/mol | H_initial = -1443 kJ/mol | | H_final = -1366 kJ/mol | ΔH_rxn^0 | -1366 kJ/mol - -1443 kJ/mol = 77.3 kJ/mol (endothermic) | | |

Gibbs free energy

 | sulfuric acid | ammonium chloride | hydrogen chloride | ammonium sulfate molecular free energy | -690 kJ/mol | -202.9 kJ/mol | -95.3 kJ/mol | -901.7 kJ/mol total free energy | -690 kJ/mol | -405.8 kJ/mol | -190.6 kJ/mol | -901.7 kJ/mol  | G_initial = -1096 kJ/mol | | G_final = -1092 kJ/mol |  ΔG_rxn^0 | -1092 kJ/mol - -1096 kJ/mol = 3.5 kJ/mol (endergonic) | | |
| sulfuric acid | ammonium chloride | hydrogen chloride | ammonium sulfate molecular free energy | -690 kJ/mol | -202.9 kJ/mol | -95.3 kJ/mol | -901.7 kJ/mol total free energy | -690 kJ/mol | -405.8 kJ/mol | -190.6 kJ/mol | -901.7 kJ/mol | G_initial = -1096 kJ/mol | | G_final = -1092 kJ/mol | ΔG_rxn^0 | -1092 kJ/mol - -1096 kJ/mol = 3.5 kJ/mol (endergonic) | | |

Equilibrium constant

Construct the equilibrium constant, K, expression for: H_2SO_4 + NH_4Cl ⟶ HCl + (NH_4)_2SO_4 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the activity expression for each chemical species. • Use the activity expressions to build the equilibrium constant expression. Write the balanced chemical equation: H_2SO_4 + 2 NH_4Cl ⟶ 2 HCl + (NH_4)_2SO_4 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i H_2SO_4 | 1 | -1 NH_4Cl | 2 | -2 HCl | 2 | 2 (NH_4)_2SO_4 | 1 | 1 Assemble the activity expressions accounting for the state of matter and ν_i: chemical species | c_i | ν_i | activity expression H_2SO_4 | 1 | -1 | ([H2SO4])^(-1) NH_4Cl | 2 | -2 | ([NH4Cl])^(-2) HCl | 2 | 2 | ([HCl])^2 (NH_4)_2SO_4 | 1 | 1 | [(NH4)2SO4] The equilibrium constant symbol in the concentration basis is: K_c Mulitply the activity expressions to arrive at the K_c expression: Answer: |   | K_c = ([H2SO4])^(-1) ([NH4Cl])^(-2) ([HCl])^2 [(NH4)2SO4] = (([HCl])^2 [(NH4)2SO4])/([H2SO4] ([NH4Cl])^2)
Construct the equilibrium constant, K, expression for: H_2SO_4 + NH_4Cl ⟶ HCl + (NH_4)_2SO_4 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the activity expression for each chemical species. • Use the activity expressions to build the equilibrium constant expression. Write the balanced chemical equation: H_2SO_4 + 2 NH_4Cl ⟶ 2 HCl + (NH_4)_2SO_4 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i H_2SO_4 | 1 | -1 NH_4Cl | 2 | -2 HCl | 2 | 2 (NH_4)_2SO_4 | 1 | 1 Assemble the activity expressions accounting for the state of matter and ν_i: chemical species | c_i | ν_i | activity expression H_2SO_4 | 1 | -1 | ([H2SO4])^(-1) NH_4Cl | 2 | -2 | ([NH4Cl])^(-2) HCl | 2 | 2 | ([HCl])^2 (NH_4)_2SO_4 | 1 | 1 | [(NH4)2SO4] The equilibrium constant symbol in the concentration basis is: K_c Mulitply the activity expressions to arrive at the K_c expression: Answer: | | K_c = ([H2SO4])^(-1) ([NH4Cl])^(-2) ([HCl])^2 [(NH4)2SO4] = (([HCl])^2 [(NH4)2SO4])/([H2SO4] ([NH4Cl])^2)

Rate of reaction

Construct the rate of reaction expression for: H_2SO_4 + NH_4Cl ⟶ HCl + (NH_4)_2SO_4 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the rate term for each chemical species. • Write the rate of reaction expression. Write the balanced chemical equation: H_2SO_4 + 2 NH_4Cl ⟶ 2 HCl + (NH_4)_2SO_4 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i H_2SO_4 | 1 | -1 NH_4Cl | 2 | -2 HCl | 2 | 2 (NH_4)_2SO_4 | 1 | 1 The rate term for each chemical species, B_i, is 1/ν_i(Δ[B_i])/(Δt) where [B_i] is the amount concentration and t is time: chemical species | c_i | ν_i | rate term H_2SO_4 | 1 | -1 | -(Δ[H2SO4])/(Δt) NH_4Cl | 2 | -2 | -1/2 (Δ[NH4Cl])/(Δt) HCl | 2 | 2 | 1/2 (Δ[HCl])/(Δt) (NH_4)_2SO_4 | 1 | 1 | (Δ[(NH4)2SO4])/(Δt) (for infinitesimal rate of change, replace Δ with d) Set the rate terms equal to each other to arrive at the rate expression: Answer: |   | rate = -(Δ[H2SO4])/(Δt) = -1/2 (Δ[NH4Cl])/(Δt) = 1/2 (Δ[HCl])/(Δt) = (Δ[(NH4)2SO4])/(Δt) (assuming constant volume and no accumulation of intermediates or side products)
Construct the rate of reaction expression for: H_2SO_4 + NH_4Cl ⟶ HCl + (NH_4)_2SO_4 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the rate term for each chemical species. • Write the rate of reaction expression. Write the balanced chemical equation: H_2SO_4 + 2 NH_4Cl ⟶ 2 HCl + (NH_4)_2SO_4 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i H_2SO_4 | 1 | -1 NH_4Cl | 2 | -2 HCl | 2 | 2 (NH_4)_2SO_4 | 1 | 1 The rate term for each chemical species, B_i, is 1/ν_i(Δ[B_i])/(Δt) where [B_i] is the amount concentration and t is time: chemical species | c_i | ν_i | rate term H_2SO_4 | 1 | -1 | -(Δ[H2SO4])/(Δt) NH_4Cl | 2 | -2 | -1/2 (Δ[NH4Cl])/(Δt) HCl | 2 | 2 | 1/2 (Δ[HCl])/(Δt) (NH_4)_2SO_4 | 1 | 1 | (Δ[(NH4)2SO4])/(Δt) (for infinitesimal rate of change, replace Δ with d) Set the rate terms equal to each other to arrive at the rate expression: Answer: | | rate = -(Δ[H2SO4])/(Δt) = -1/2 (Δ[NH4Cl])/(Δt) = 1/2 (Δ[HCl])/(Δt) = (Δ[(NH4)2SO4])/(Δt) (assuming constant volume and no accumulation of intermediates or side products)

Chemical names and formulas

 | sulfuric acid | ammonium chloride | hydrogen chloride | ammonium sulfate formula | H_2SO_4 | NH_4Cl | HCl | (NH_4)_2SO_4 Hill formula | H_2O_4S | ClH_4N | ClH | H_8N_2O_4S name | sulfuric acid | ammonium chloride | hydrogen chloride | ammonium sulfate
| sulfuric acid | ammonium chloride | hydrogen chloride | ammonium sulfate formula | H_2SO_4 | NH_4Cl | HCl | (NH_4)_2SO_4 Hill formula | H_2O_4S | ClH_4N | ClH | H_8N_2O_4S name | sulfuric acid | ammonium chloride | hydrogen chloride | ammonium sulfate

Substance properties

 | sulfuric acid | ammonium chloride | hydrogen chloride | ammonium sulfate molar mass | 98.07 g/mol | 53.49 g/mol | 36.46 g/mol | 132.1 g/mol phase | liquid (at STP) | solid (at STP) | gas (at STP) | solid (at STP) melting point | 10.371 °C | 340 °C | -114.17 °C | 280 °C boiling point | 279.6 °C | | -85 °C |  density | 1.8305 g/cm^3 | 1.5256 g/cm^3 | 0.00149 g/cm^3 (at 25 °C) | 1.77 g/cm^3 solubility in water | very soluble | soluble | miscible |  surface tension | 0.0735 N/m | | |  dynamic viscosity | 0.021 Pa s (at 25 °C) | | |  odor | odorless | | | odorless
| sulfuric acid | ammonium chloride | hydrogen chloride | ammonium sulfate molar mass | 98.07 g/mol | 53.49 g/mol | 36.46 g/mol | 132.1 g/mol phase | liquid (at STP) | solid (at STP) | gas (at STP) | solid (at STP) melting point | 10.371 °C | 340 °C | -114.17 °C | 280 °C boiling point | 279.6 °C | | -85 °C | density | 1.8305 g/cm^3 | 1.5256 g/cm^3 | 0.00149 g/cm^3 (at 25 °C) | 1.77 g/cm^3 solubility in water | very soluble | soluble | miscible | surface tension | 0.0735 N/m | | | dynamic viscosity | 0.021 Pa s (at 25 °C) | | | odor | odorless | | | odorless

Units