Input interpretation
![hydrazine monohydrochloride | relative molecular mass](../image_source/3978af1ae79179d2e2be65897edaf1d3.png)
hydrazine monohydrochloride | relative molecular mass
Result
![Find the relative molecular mass, M_r, for hydrazine monohydrochloride: M_r = sum _iN_im_i/m_u Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: NH_2NH_2·HCl Use the chemical formula, NH_2NH_2·HCl, to count the number of atoms, N_i, for each element: | N_i Cl (chlorine) | 1 H (hydrogen) | 5 N (nitrogen) | 2 Look up the atomic mass, m_i, in unified atomic mass units, u, for each element in the periodic table. Since m_i is divided by the atomic mass constant, m_u, the result is a unitless relative atomic mass: | N_i | m_i/m_u Cl (chlorine) | 1 | 35.45 H (hydrogen) | 5 | 1.008 N (nitrogen) | 2 | 14.007 Multiply N_i by m_i/m_u to compute the relative mass for each element. Then sum those values to compute the relative molecular mass, M_r: Answer: | | | N_i | m_i/m_u | relative mass Cl (chlorine) | 1 | 35.45 | 1 × 35.45 = 35.45 H (hydrogen) | 5 | 1.008 | 5 × 1.008 = 5.040 N (nitrogen) | 2 | 14.007 | 2 × 14.007 = 28.014 M_r = 35.45 + 5.040 + 28.014 = 68.50](../image_source/6d0a5d985ac253b0cabd4c57ab50f5bc.png)
Find the relative molecular mass, M_r, for hydrazine monohydrochloride: M_r = sum _iN_im_i/m_u Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: NH_2NH_2·HCl Use the chemical formula, NH_2NH_2·HCl, to count the number of atoms, N_i, for each element: | N_i Cl (chlorine) | 1 H (hydrogen) | 5 N (nitrogen) | 2 Look up the atomic mass, m_i, in unified atomic mass units, u, for each element in the periodic table. Since m_i is divided by the atomic mass constant, m_u, the result is a unitless relative atomic mass: | N_i | m_i/m_u Cl (chlorine) | 1 | 35.45 H (hydrogen) | 5 | 1.008 N (nitrogen) | 2 | 14.007 Multiply N_i by m_i/m_u to compute the relative mass for each element. Then sum those values to compute the relative molecular mass, M_r: Answer: | | | N_i | m_i/m_u | relative mass Cl (chlorine) | 1 | 35.45 | 1 × 35.45 = 35.45 H (hydrogen) | 5 | 1.008 | 5 × 1.008 = 5.040 N (nitrogen) | 2 | 14.007 | 2 × 14.007 = 28.014 M_r = 35.45 + 5.040 + 28.014 = 68.50
Comparisons
![≈ ( 0.095 ≈ 1/11 ) × relative molecular mass of fullerene ( ≈ 721 )](../image_source/bdc43edab05f8793295c9d1b8a0ae465.png)
≈ ( 0.095 ≈ 1/11 ) × relative molecular mass of fullerene ( ≈ 721 )
![≈ 0.35 × relative molecular mass of caffeine ( ≈ 194 )](../image_source/8719b6e98dcd78519eeedc40d21b9376.png)
≈ 0.35 × relative molecular mass of caffeine ( ≈ 194 )
![≈ 1.2 × relative molecular mass of sodium chloride ( ≈ 58 )](../image_source/fa7370370b8aeb72a4e9c9272710d2f6.png)
≈ 1.2 × relative molecular mass of sodium chloride ( ≈ 58 )
Corresponding quantities
![Molar mass M from M = M_uM_r: | 69 g/mol (grams per mole)](../image_source/c227eedbb82cbfe917f1054dbb104c19.png)
Molar mass M from M = M_uM_r: | 69 g/mol (grams per mole)
![Molecular mass m from m = M_rM_u/N_A: | 1.1×10^-22 grams | 1.1×10^-25 kg (kilograms)](../image_source/224a444ff242b37f9a1f11b981a5f516.png)
Molecular mass m from m = M_rM_u/N_A: | 1.1×10^-22 grams | 1.1×10^-25 kg (kilograms)