O2 + C6H5OH = H2O + CO2

oxygen + phenol ⟶ water + carbon dioxide

Balance the chemical equation algebraically: + ⟶ + Add stoichiometric coefficients, c_i, to the reactants and products: c_1 + c_2 ⟶ c_3 + c_4 Set the number of atoms in the reactants equal to the number of atoms in the products for O, C and H: O: | 2 c_1 + c_2 = c_3 + 2 c_4 C: | 6 c_2 = c_4 H: | 6 c_2 = 2 c_3 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_2 = 1 and solve the system of equations for the remaining coefficients: c_1 = 7 c_2 = 1 c_3 = 3 c_4 = 6 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | 7 + ⟶ 3 + 6

+ ⟶ +

oxygen + phenol ⟶ water + carbon dioxide

| oxygen | phenol | water | carbon dioxide molecular enthalpy | 0 kJ/mol | -165.1 kJ/mol | -285.8 kJ/mol | -393.5 kJ/mol total enthalpy | 0 kJ/mol | -165.1 kJ/mol | -857.5 kJ/mol | -2361 kJ/mol | H_initial = -165.1 kJ/mol | | H_final = -3218 kJ/mol | ΔH_rxn^0 | -3218 kJ/mol - -165.1 kJ/mol = -3053 kJ/mol (exothermic) | | |

| oxygen | phenol | water | carbon dioxide Hill formula | O_2 | C_6H_6O | H_2O | CO_2 name | oxygen | phenol | water | carbon dioxide IUPAC name | molecular oxygen | phenol | water | carbon dioxide