Input interpretation
![chloroplatinic acid hydrate | molar mass](../image_source/d8f78396edbdbc8218ca278010606ef7.png)
chloroplatinic acid hydrate | molar mass
Result
![Find the molar mass, M, for chloroplatinic acid hydrate: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: H_2PtCl_6·aq Use the chemical formula to count the number of atoms, N_i, for each element: | N_i Cl (chlorine) | 6 H (hydrogen) | 4 O (oxygen) | 1 Pt (platinum) | 1 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) Cl (chlorine) | 6 | 35.45 H (hydrogen) | 4 | 1.008 O (oxygen) | 1 | 15.999 Pt (platinum) | 1 | 195.084 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) Cl (chlorine) | 6 | 35.45 | 6 × 35.45 = 212.70 H (hydrogen) | 4 | 1.008 | 4 × 1.008 = 4.032 O (oxygen) | 1 | 15.999 | 1 × 15.999 = 15.999 Pt (platinum) | 1 | 195.084 | 1 × 195.084 = 195.084 M = 212.70 g/mol + 4.032 g/mol + 15.999 g/mol + 195.084 g/mol = 427.82 g/mol](../image_source/0710d46e9057ff3c864a72ec752d5fa4.png)
Find the molar mass, M, for chloroplatinic acid hydrate: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: H_2PtCl_6·aq Use the chemical formula to count the number of atoms, N_i, for each element: | N_i Cl (chlorine) | 6 H (hydrogen) | 4 O (oxygen) | 1 Pt (platinum) | 1 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) Cl (chlorine) | 6 | 35.45 H (hydrogen) | 4 | 1.008 O (oxygen) | 1 | 15.999 Pt (platinum) | 1 | 195.084 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) Cl (chlorine) | 6 | 35.45 | 6 × 35.45 = 212.70 H (hydrogen) | 4 | 1.008 | 4 × 1.008 = 4.032 O (oxygen) | 1 | 15.999 | 1 × 15.999 = 15.999 Pt (platinum) | 1 | 195.084 | 1 × 195.084 = 195.084 M = 212.70 g/mol + 4.032 g/mol + 15.999 g/mol + 195.084 g/mol = 427.82 g/mol
Unit conversion
![0.4278 kg/mol (kilograms per mole)](../image_source/776483c42ff19eca322817223ae3bf9a.png)
0.4278 kg/mol (kilograms per mole)
Comparisons
![≈ 0.59 × molar mass of fullerene ( ≈ 721 g/mol )](../image_source/114b43a5d2a8860dc1e5e3835e961924.png)
≈ 0.59 × molar mass of fullerene ( ≈ 721 g/mol )
![≈ 2.2 × molar mass of caffeine ( ≈ 194 g/mol )](../image_source/451fe603b856536390480d0802d4b891.png)
≈ 2.2 × molar mass of caffeine ( ≈ 194 g/mol )
![≈ 7.3 × molar mass of sodium chloride ( ≈ 58 g/mol )](../image_source/ef397b18efb4074bdaa87767d5a80234.png)
≈ 7.3 × molar mass of sodium chloride ( ≈ 58 g/mol )
Corresponding quantities
![Mass of a molecule m from m = M/N_A: | 7.1×10^-22 grams | 7.1×10^-25 kg (kilograms) | 428 u (unified atomic mass units) | 428 Da (daltons)](../image_source/73b7c459890fac8d894f0be8969b4bcf.png)
Mass of a molecule m from m = M/N_A: | 7.1×10^-22 grams | 7.1×10^-25 kg (kilograms) | 428 u (unified atomic mass units) | 428 Da (daltons)
![Relative molecular mass M_r from M_r = M_u/M: | 428](../image_source/ff39f6c3dcb4f5f5f4de7976da1611a5.png)
Relative molecular mass M_r from M_r = M_u/M: | 428