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hydrogen carbonate anion

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hydrogen carbonate anion
hydrogen carbonate anion

Lewis structure

Draw the Lewis structure of hydrogen carbonate anion. Start by drawing the overall structure of the molecule, ignoring potential double and triple bonds:  Count the total valence electrons of the carbon (n_C, val = 4), hydrogen (n_H, val = 1), and oxygen (n_O, val = 6) atoms, including the net charge: n_C, val + n_H, val + 3 n_O, val - n_charge = 24 Calculate the number of electrons needed to completely fill the valence shells for carbon (n_C, full = 8), hydrogen (n_H, full = 2), and oxygen (n_O, full = 8): n_C, full + n_H, full + 3 n_O, full = 34 Subtracting these two numbers shows that 34 - 24 = 10 bonding electrons are needed. Each bond has two electrons, so in addition to the 4 bonds already present in the diagram add 1 bond. To minimize formal charge oxygen wants 2 bonds and carbon wants 4 bonds. Identify the atoms that want additional bonds and the number of electrons remaining on each atom. The net charge has been given to the most electronegative atom, oxygen:  Fill in the 1 bond by pairing electrons between adjacent highlighted atoms, noting the formal charges of the atoms. Double bonding carbon to the other highlighted oxygen atom would result in an equivalent molecule: Answer: |   |
Draw the Lewis structure of hydrogen carbonate anion. Start by drawing the overall structure of the molecule, ignoring potential double and triple bonds: Count the total valence electrons of the carbon (n_C, val = 4), hydrogen (n_H, val = 1), and oxygen (n_O, val = 6) atoms, including the net charge: n_C, val + n_H, val + 3 n_O, val - n_charge = 24 Calculate the number of electrons needed to completely fill the valence shells for carbon (n_C, full = 8), hydrogen (n_H, full = 2), and oxygen (n_O, full = 8): n_C, full + n_H, full + 3 n_O, full = 34 Subtracting these two numbers shows that 34 - 24 = 10 bonding electrons are needed. Each bond has two electrons, so in addition to the 4 bonds already present in the diagram add 1 bond. To minimize formal charge oxygen wants 2 bonds and carbon wants 4 bonds. Identify the atoms that want additional bonds and the number of electrons remaining on each atom. The net charge has been given to the most electronegative atom, oxygen: Fill in the 1 bond by pairing electrons between adjacent highlighted atoms, noting the formal charges of the atoms. Double bonding carbon to the other highlighted oxygen atom would result in an equivalent molecule: Answer: | |

General properties

formula | (HCO_3)^- net ionic charge | -1 alternate names | bicarbonate | hydrogen trioxocarbonate | hydrogen trioxidocarbonate | hydrogen carbonate | hydrogen carbonate(1-)
formula | (HCO_3)^- net ionic charge | -1 alternate names | bicarbonate | hydrogen trioxocarbonate | hydrogen trioxidocarbonate | hydrogen carbonate | hydrogen carbonate(1-)

Ionic radius

thermochemical radius | 156 pm
thermochemical radius | 156 pm

Units

Other properties

ion class | anions | biomolecule ions | ionic conjugate bases | oxoanions | polyatomic ions | ionic weak acids common sources of ion | ammonium bicarbonate (1 eq)
ion class | anions | biomolecule ions | ionic conjugate bases | oxoanions | polyatomic ions | ionic weak acids common sources of ion | ammonium bicarbonate (1 eq)

Thermodynamic properties

molar free energy of formation Δ_fG° | aqueous | -586.8 kJ/mol (kilojoules per mole) molar heat of formation Δ_fH° | aqueous | -692 kJ/mol (kilojoules per mole) molar entropy S° | aqueous | 91.2 J/(mol K) (joules per mole kelvin)
molar free energy of formation Δ_fG° | aqueous | -586.8 kJ/mol (kilojoules per mole) molar heat of formation Δ_fH° | aqueous | -692 kJ/mol (kilojoules per mole) molar entropy S° | aqueous | 91.2 J/(mol K) (joules per mole kelvin)