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KMnO4 + (COOH)2 = H2O + CO2 + KOH + MnO2

Input interpretation

potassium permanganate + oxalic acid ⟶ water + carbon dioxide + potassium hydroxide + manganese dioxide
potassium permanganate + oxalic acid ⟶ water + carbon dioxide + potassium hydroxide + manganese dioxide

Balanced equation

Balance the chemical equation algebraically:  + ⟶ + + +  Add stoichiometric coefficients, c_i, to the reactants and products: c_1 + c_2 ⟶ c_3 + c_4 + c_5 + c_6  Set the number of atoms in the reactants equal to the number of atoms in the products for K, Mn, O, C and H: K: | c_1 = c_5 Mn: | c_1 = c_6 O: | 4 c_1 + 4 c_2 = c_3 + 2 c_4 + c_5 + 2 c_6 C: | 2 c_2 = c_4 H: | 2 c_2 = 2 c_3 + c_5 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_1 = 1 and solve the system of equations for the remaining coefficients: c_1 = 1 c_2 = 3/2 c_3 = 1 c_4 = 3 c_5 = 1 c_6 = 1 Multiply by the least common denominator, 2, to eliminate fractional coefficients: c_1 = 2 c_2 = 3 c_3 = 2 c_4 = 6 c_5 = 2 c_6 = 2 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: |   | 2 + 3 ⟶ 2 + 6 + 2 + 2
Balance the chemical equation algebraically: + ⟶ + + + Add stoichiometric coefficients, c_i, to the reactants and products: c_1 + c_2 ⟶ c_3 + c_4 + c_5 + c_6 Set the number of atoms in the reactants equal to the number of atoms in the products for K, Mn, O, C and H: K: | c_1 = c_5 Mn: | c_1 = c_6 O: | 4 c_1 + 4 c_2 = c_3 + 2 c_4 + c_5 + 2 c_6 C: | 2 c_2 = c_4 H: | 2 c_2 = 2 c_3 + c_5 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_1 = 1 and solve the system of equations for the remaining coefficients: c_1 = 1 c_2 = 3/2 c_3 = 1 c_4 = 3 c_5 = 1 c_6 = 1 Multiply by the least common denominator, 2, to eliminate fractional coefficients: c_1 = 2 c_2 = 3 c_3 = 2 c_4 = 6 c_5 = 2 c_6 = 2 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | 2 + 3 ⟶ 2 + 6 + 2 + 2

Structures

 + ⟶ + + +
+ ⟶ + + +

Names

potassium permanganate + oxalic acid ⟶ water + carbon dioxide + potassium hydroxide + manganese dioxide
potassium permanganate + oxalic acid ⟶ water + carbon dioxide + potassium hydroxide + manganese dioxide

Chemical names and formulas

 | potassium permanganate | oxalic acid | water | carbon dioxide | potassium hydroxide | manganese dioxide Hill formula | KMnO_4 | C_2H_2O_4 | H_2O | CO_2 | HKO | MnO_2 name | potassium permanganate | oxalic acid | water | carbon dioxide | potassium hydroxide | manganese dioxide IUPAC name | potassium permanganate | oxalic acid | water | carbon dioxide | potassium hydroxide | dioxomanganese
| potassium permanganate | oxalic acid | water | carbon dioxide | potassium hydroxide | manganese dioxide Hill formula | KMnO_4 | C_2H_2O_4 | H_2O | CO_2 | HKO | MnO_2 name | potassium permanganate | oxalic acid | water | carbon dioxide | potassium hydroxide | manganese dioxide IUPAC name | potassium permanganate | oxalic acid | water | carbon dioxide | potassium hydroxide | dioxomanganese