Input interpretation
![potassium hydroxide + manganese(II) chloride + KClO ⟶ water + potassium permanganate + potassium chloride](../image_source/d5792636852c63de725c83444772bd80.png)
potassium hydroxide + manganese(II) chloride + KClO ⟶ water + potassium permanganate + potassium chloride
Balanced equation
![Balance the chemical equation algebraically: + + KClO ⟶ + + Add stoichiometric coefficients, c_i, to the reactants and products: c_1 + c_2 + c_3 KClO ⟶ c_4 + c_5 + c_6 Set the number of atoms in the reactants equal to the number of atoms in the products for H, K, O, Cl and Mn: H: | c_1 = 2 c_4 K: | c_1 + c_3 = c_5 + c_6 O: | c_1 + c_3 = c_4 + 4 c_5 Cl: | 2 c_2 + c_3 = c_6 Mn: | c_2 = c_5 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_2 = 1 and solve the system of equations for the remaining coefficients: c_1 = 3 c_2 = 1 c_3 = 5/2 c_4 = 3/2 c_5 = 1 c_6 = 9/2 Multiply by the least common denominator, 2, to eliminate fractional coefficients: c_1 = 6 c_2 = 2 c_3 = 5 c_4 = 3 c_5 = 2 c_6 = 9 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | 6 + 2 + 5 KClO ⟶ 3 + 2 + 9](../image_source/4b9e2f6488b735a860780f0cc6c4a063.png)
Balance the chemical equation algebraically: + + KClO ⟶ + + Add stoichiometric coefficients, c_i, to the reactants and products: c_1 + c_2 + c_3 KClO ⟶ c_4 + c_5 + c_6 Set the number of atoms in the reactants equal to the number of atoms in the products for H, K, O, Cl and Mn: H: | c_1 = 2 c_4 K: | c_1 + c_3 = c_5 + c_6 O: | c_1 + c_3 = c_4 + 4 c_5 Cl: | 2 c_2 + c_3 = c_6 Mn: | c_2 = c_5 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_2 = 1 and solve the system of equations for the remaining coefficients: c_1 = 3 c_2 = 1 c_3 = 5/2 c_4 = 3/2 c_5 = 1 c_6 = 9/2 Multiply by the least common denominator, 2, to eliminate fractional coefficients: c_1 = 6 c_2 = 2 c_3 = 5 c_4 = 3 c_5 = 2 c_6 = 9 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | 6 + 2 + 5 KClO ⟶ 3 + 2 + 9
Structures
![+ + KClO ⟶ + +](../image_source/7078544a143cc714fddf5335d22b2761.png)
+ + KClO ⟶ + +
Names
![potassium hydroxide + manganese(II) chloride + KClO ⟶ water + potassium permanganate + potassium chloride](../image_source/57a379516579392068dce05d84071e5c.png)
potassium hydroxide + manganese(II) chloride + KClO ⟶ water + potassium permanganate + potassium chloride
Chemical names and formulas
![| potassium hydroxide | manganese(II) chloride | KClO | water | potassium permanganate | potassium chloride formula | | | KClO | | | Hill formula | HKO | Cl_2Mn | ClKO | H_2O | KMnO_4 | ClK name | potassium hydroxide | manganese(II) chloride | | water | potassium permanganate | potassium chloride IUPAC name | potassium hydroxide | dichloromanganese | | water | potassium permanganate | potassium chloride](../image_source/465e399781583b6806b160ca7aa2835f.png)
| potassium hydroxide | manganese(II) chloride | KClO | water | potassium permanganate | potassium chloride formula | | | KClO | | | Hill formula | HKO | Cl_2Mn | ClKO | H_2O | KMnO_4 | ClK name | potassium hydroxide | manganese(II) chloride | | water | potassium permanganate | potassium chloride IUPAC name | potassium hydroxide | dichloromanganese | | water | potassium permanganate | potassium chloride