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KOH + MnCl2 + KClO = H2O + KMnO4 + KCl

Input interpretation

potassium hydroxide + manganese(II) chloride + KClO ⟶ water + potassium permanganate + potassium chloride
potassium hydroxide + manganese(II) chloride + KClO ⟶ water + potassium permanganate + potassium chloride

Balanced equation

Balance the chemical equation algebraically:  + + KClO ⟶ + +  Add stoichiometric coefficients, c_i, to the reactants and products: c_1 + c_2 + c_3 KClO ⟶ c_4 + c_5 + c_6  Set the number of atoms in the reactants equal to the number of atoms in the products for H, K, O, Cl and Mn: H: | c_1 = 2 c_4 K: | c_1 + c_3 = c_5 + c_6 O: | c_1 + c_3 = c_4 + 4 c_5 Cl: | 2 c_2 + c_3 = c_6 Mn: | c_2 = c_5 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_2 = 1 and solve the system of equations for the remaining coefficients: c_1 = 3 c_2 = 1 c_3 = 5/2 c_4 = 3/2 c_5 = 1 c_6 = 9/2 Multiply by the least common denominator, 2, to eliminate fractional coefficients: c_1 = 6 c_2 = 2 c_3 = 5 c_4 = 3 c_5 = 2 c_6 = 9 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: |   | 6 + 2 + 5 KClO ⟶ 3 + 2 + 9
Balance the chemical equation algebraically: + + KClO ⟶ + + Add stoichiometric coefficients, c_i, to the reactants and products: c_1 + c_2 + c_3 KClO ⟶ c_4 + c_5 + c_6 Set the number of atoms in the reactants equal to the number of atoms in the products for H, K, O, Cl and Mn: H: | c_1 = 2 c_4 K: | c_1 + c_3 = c_5 + c_6 O: | c_1 + c_3 = c_4 + 4 c_5 Cl: | 2 c_2 + c_3 = c_6 Mn: | c_2 = c_5 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_2 = 1 and solve the system of equations for the remaining coefficients: c_1 = 3 c_2 = 1 c_3 = 5/2 c_4 = 3/2 c_5 = 1 c_6 = 9/2 Multiply by the least common denominator, 2, to eliminate fractional coefficients: c_1 = 6 c_2 = 2 c_3 = 5 c_4 = 3 c_5 = 2 c_6 = 9 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | 6 + 2 + 5 KClO ⟶ 3 + 2 + 9

Structures

 + + KClO ⟶ + +
+ + KClO ⟶ + +

Names

potassium hydroxide + manganese(II) chloride + KClO ⟶ water + potassium permanganate + potassium chloride
potassium hydroxide + manganese(II) chloride + KClO ⟶ water + potassium permanganate + potassium chloride

Chemical names and formulas

 | potassium hydroxide | manganese(II) chloride | KClO | water | potassium permanganate | potassium chloride formula | | | KClO | | |  Hill formula | HKO | Cl_2Mn | ClKO | H_2O | KMnO_4 | ClK name | potassium hydroxide | manganese(II) chloride | | water | potassium permanganate | potassium chloride IUPAC name | potassium hydroxide | dichloromanganese | | water | potassium permanganate | potassium chloride
| potassium hydroxide | manganese(II) chloride | KClO | water | potassium permanganate | potassium chloride formula | | | KClO | | | Hill formula | HKO | Cl_2Mn | ClKO | H_2O | KMnO_4 | ClK name | potassium hydroxide | manganese(II) chloride | | water | potassium permanganate | potassium chloride IUPAC name | potassium hydroxide | dichloromanganese | | water | potassium permanganate | potassium chloride