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Fe + Na2SO4 = FeSO4 + Na

Input interpretation

Fe iron + Na_2SO_4 sodium sulfate ⟶ FeSO_4 duretter + Na sodium
Fe iron + Na_2SO_4 sodium sulfate ⟶ FeSO_4 duretter + Na sodium

Balanced equation

Balance the chemical equation algebraically: Fe + Na_2SO_4 ⟶ FeSO_4 + Na Add stoichiometric coefficients, c_i, to the reactants and products: c_1 Fe + c_2 Na_2SO_4 ⟶ c_3 FeSO_4 + c_4 Na Set the number of atoms in the reactants equal to the number of atoms in the products for Fe, Na, O and S: Fe: | c_1 = c_3 Na: | 2 c_2 = c_4 O: | 4 c_2 = 4 c_3 S: | c_2 = c_3 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_1 = 1 and solve the system of equations for the remaining coefficients: c_1 = 1 c_2 = 1 c_3 = 1 c_4 = 2 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: |   | Fe + Na_2SO_4 ⟶ FeSO_4 + 2 Na
Balance the chemical equation algebraically: Fe + Na_2SO_4 ⟶ FeSO_4 + Na Add stoichiometric coefficients, c_i, to the reactants and products: c_1 Fe + c_2 Na_2SO_4 ⟶ c_3 FeSO_4 + c_4 Na Set the number of atoms in the reactants equal to the number of atoms in the products for Fe, Na, O and S: Fe: | c_1 = c_3 Na: | 2 c_2 = c_4 O: | 4 c_2 = 4 c_3 S: | c_2 = c_3 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_1 = 1 and solve the system of equations for the remaining coefficients: c_1 = 1 c_2 = 1 c_3 = 1 c_4 = 2 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | Fe + Na_2SO_4 ⟶ FeSO_4 + 2 Na

Structures

 + ⟶ +
+ ⟶ +

Names

iron + sodium sulfate ⟶ duretter + sodium
iron + sodium sulfate ⟶ duretter + sodium

Equilibrium constant

Construct the equilibrium constant, K, expression for: Fe + Na_2SO_4 ⟶ FeSO_4 + Na Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the activity expression for each chemical species. • Use the activity expressions to build the equilibrium constant expression. Write the balanced chemical equation: Fe + Na_2SO_4 ⟶ FeSO_4 + 2 Na Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i Fe | 1 | -1 Na_2SO_4 | 1 | -1 FeSO_4 | 1 | 1 Na | 2 | 2 Assemble the activity expressions accounting for the state of matter and ν_i: chemical species | c_i | ν_i | activity expression Fe | 1 | -1 | ([Fe])^(-1) Na_2SO_4 | 1 | -1 | ([Na2SO4])^(-1) FeSO_4 | 1 | 1 | [FeSO4] Na | 2 | 2 | ([Na])^2 The equilibrium constant symbol in the concentration basis is: K_c Mulitply the activity expressions to arrive at the K_c expression: Answer: |   | K_c = ([Fe])^(-1) ([Na2SO4])^(-1) [FeSO4] ([Na])^2 = ([FeSO4] ([Na])^2)/([Fe] [Na2SO4])
Construct the equilibrium constant, K, expression for: Fe + Na_2SO_4 ⟶ FeSO_4 + Na Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the activity expression for each chemical species. • Use the activity expressions to build the equilibrium constant expression. Write the balanced chemical equation: Fe + Na_2SO_4 ⟶ FeSO_4 + 2 Na Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i Fe | 1 | -1 Na_2SO_4 | 1 | -1 FeSO_4 | 1 | 1 Na | 2 | 2 Assemble the activity expressions accounting for the state of matter and ν_i: chemical species | c_i | ν_i | activity expression Fe | 1 | -1 | ([Fe])^(-1) Na_2SO_4 | 1 | -1 | ([Na2SO4])^(-1) FeSO_4 | 1 | 1 | [FeSO4] Na | 2 | 2 | ([Na])^2 The equilibrium constant symbol in the concentration basis is: K_c Mulitply the activity expressions to arrive at the K_c expression: Answer: | | K_c = ([Fe])^(-1) ([Na2SO4])^(-1) [FeSO4] ([Na])^2 = ([FeSO4] ([Na])^2)/([Fe] [Na2SO4])

Rate of reaction

Construct the rate of reaction expression for: Fe + Na_2SO_4 ⟶ FeSO_4 + Na Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the rate term for each chemical species. • Write the rate of reaction expression. Write the balanced chemical equation: Fe + Na_2SO_4 ⟶ FeSO_4 + 2 Na Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i Fe | 1 | -1 Na_2SO_4 | 1 | -1 FeSO_4 | 1 | 1 Na | 2 | 2 The rate term for each chemical species, B_i, is 1/ν_i(Δ[B_i])/(Δt) where [B_i] is the amount concentration and t is time: chemical species | c_i | ν_i | rate term Fe | 1 | -1 | -(Δ[Fe])/(Δt) Na_2SO_4 | 1 | -1 | -(Δ[Na2SO4])/(Δt) FeSO_4 | 1 | 1 | (Δ[FeSO4])/(Δt) Na | 2 | 2 | 1/2 (Δ[Na])/(Δt) (for infinitesimal rate of change, replace Δ with d) Set the rate terms equal to each other to arrive at the rate expression: Answer: |   | rate = -(Δ[Fe])/(Δt) = -(Δ[Na2SO4])/(Δt) = (Δ[FeSO4])/(Δt) = 1/2 (Δ[Na])/(Δt) (assuming constant volume and no accumulation of intermediates or side products)
Construct the rate of reaction expression for: Fe + Na_2SO_4 ⟶ FeSO_4 + Na Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the rate term for each chemical species. • Write the rate of reaction expression. Write the balanced chemical equation: Fe + Na_2SO_4 ⟶ FeSO_4 + 2 Na Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i Fe | 1 | -1 Na_2SO_4 | 1 | -1 FeSO_4 | 1 | 1 Na | 2 | 2 The rate term for each chemical species, B_i, is 1/ν_i(Δ[B_i])/(Δt) where [B_i] is the amount concentration and t is time: chemical species | c_i | ν_i | rate term Fe | 1 | -1 | -(Δ[Fe])/(Δt) Na_2SO_4 | 1 | -1 | -(Δ[Na2SO4])/(Δt) FeSO_4 | 1 | 1 | (Δ[FeSO4])/(Δt) Na | 2 | 2 | 1/2 (Δ[Na])/(Δt) (for infinitesimal rate of change, replace Δ with d) Set the rate terms equal to each other to arrive at the rate expression: Answer: | | rate = -(Δ[Fe])/(Δt) = -(Δ[Na2SO4])/(Δt) = (Δ[FeSO4])/(Δt) = 1/2 (Δ[Na])/(Δt) (assuming constant volume and no accumulation of intermediates or side products)

Chemical names and formulas

 | iron | sodium sulfate | duretter | sodium formula | Fe | Na_2SO_4 | FeSO_4 | Na Hill formula | Fe | Na_2O_4S | FeO_4S | Na name | iron | sodium sulfate | duretter | sodium IUPAC name | iron | disodium sulfate | iron(+2) cation sulfate | sodium
| iron | sodium sulfate | duretter | sodium formula | Fe | Na_2SO_4 | FeSO_4 | Na Hill formula | Fe | Na_2O_4S | FeO_4S | Na name | iron | sodium sulfate | duretter | sodium IUPAC name | iron | disodium sulfate | iron(+2) cation sulfate | sodium

Substance properties

 | iron | sodium sulfate | duretter | sodium molar mass | 55.845 g/mol | 142.04 g/mol | 151.9 g/mol | 22.98976928 g/mol phase | solid (at STP) | solid (at STP) | | solid (at STP) melting point | 1535 °C | 884 °C | | 97.8 °C boiling point | 2750 °C | 1429 °C | | 883 °C density | 7.874 g/cm^3 | 2.68 g/cm^3 | 2.841 g/cm^3 | 0.968 g/cm^3 solubility in water | insoluble | soluble | | decomposes dynamic viscosity | | | | 1.413×10^-5 Pa s (at 527 °C)
| iron | sodium sulfate | duretter | sodium molar mass | 55.845 g/mol | 142.04 g/mol | 151.9 g/mol | 22.98976928 g/mol phase | solid (at STP) | solid (at STP) | | solid (at STP) melting point | 1535 °C | 884 °C | | 97.8 °C boiling point | 2750 °C | 1429 °C | | 883 °C density | 7.874 g/cm^3 | 2.68 g/cm^3 | 2.841 g/cm^3 | 0.968 g/cm^3 solubility in water | insoluble | soluble | | decomposes dynamic viscosity | | | | 1.413×10^-5 Pa s (at 527 °C)

Units