Input interpretation
iodine trichloride | orbital hybridization
Result
First draw the structure diagram for iodine trichloride, and for every non-hydrogen atom, count the σ-bonds. Note that double and triple bonds consist of one σ-bond together with one or two π-bonds: Identify those atoms with lone pairs: Find the steric number by adding the lone pair count to the number of σ-bonds: Consult the following chart to determine the hybridization from the steric number: steric number | hybridization 2 | sp 3 | sp^2 4 | sp^3 5 | dsp^3 6 | d^2sp^3 7 | d^3sp^3 Now assign the hybridization for each atom: Answer: | |
Chemical names and formulas
formula | ICl_3 Hill formula | Cl_3I name | iodine trichloride alternate names | iodine chloride | trichloroiodine mass fractions | Cl (chlorine) 45.6% | I (iodine) 54.4%