SnCl4 = Cl2 + Sn

SnCl_4 stannic chloride ⟶ Cl_2 chlorine + Sn white tin

Balance the chemical equation algebraically: SnCl_4 ⟶ Cl_2 + Sn Add stoichiometric coefficients, c_i, to the reactants and products: c_1 SnCl_4 ⟶ c_2 Cl_2 + c_3 Sn Set the number of atoms in the reactants equal to the number of atoms in the products for Cl and Sn: Cl: | 4 c_1 = 2 c_2 Sn: | c_1 = c_3 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_1 = 1 and solve the system of equations for the remaining coefficients: c_1 = 1 c_2 = 2 c_3 = 1 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | SnCl_4 ⟶ 2 Cl_2 + Sn

⟶ +

stannic chloride ⟶ chlorine + white tin

Construct the equilibrium constant, K, expression for: SnCl_4 ⟶ Cl_2 + Sn Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the activity expression for each chemical species. • Use the activity expressions to build the equilibrium constant expression. Write the balanced chemical equation: SnCl_4 ⟶ 2 Cl_2 + Sn Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i SnCl_4 | 1 | -1 Cl_2 | 2 | 2 Sn | 1 | 1 Assemble the activity expressions accounting for the state of matter and ν_i: chemical species | c_i | ν_i | activity expression SnCl_4 | 1 | -1 | ([SnCl4])^(-1) Cl_2 | 2 | 2 | ([Cl2])^2 Sn | 1 | 1 | [Sn] The equilibrium constant symbol in the concentration basis is: K_c Mulitply the activity expressions to arrive at the K_c expression: Answer: | | K_c = ([SnCl4])^(-1) ([Cl2])^2 [Sn] = (([Cl2])^2 [Sn])/([SnCl4])

Construct the rate of reaction expression for: SnCl_4 ⟶ Cl_2 + Sn Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the rate term for each chemical species. • Write the rate of reaction expression. Write the balanced chemical equation: SnCl_4 ⟶ 2 Cl_2 + Sn Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i SnCl_4 | 1 | -1 Cl_2 | 2 | 2 Sn | 1 | 1 The rate term for each chemical species, B_i, is 1/ν_i(Δ[B_i])/(Δt) where [B_i] is the amount concentration and t is time: chemical species | c_i | ν_i | rate term SnCl_4 | 1 | -1 | -(Δ[SnCl4])/(Δt) Cl_2 | 2 | 2 | 1/2 (Δ[Cl2])/(Δt) Sn | 1 | 1 | (Δ[Sn])/(Δt) (for infinitesimal rate of change, replace Δ with d) Set the rate terms equal to each other to arrive at the rate expression: Answer: | | rate = -(Δ[SnCl4])/(Δt) = 1/2 (Δ[Cl2])/(Δt) = (Δ[Sn])/(Δt) (assuming constant volume and no accumulation of intermediates or side products)

| stannic chloride | chlorine | white tin formula | SnCl_4 | Cl_2 | Sn Hill formula | Cl_4Sn | Cl_2 | Sn name | stannic chloride | chlorine | white tin IUPAC name | tetrachlorostannane | molecular chlorine | tin

| stannic chloride | chlorine | white tin molar mass | 260.5 g/mol | 70.9 g/mol | 118.71 g/mol phase | liquid (at STP) | gas (at STP) | solid (at STP) melting point | -33 °C | -101 °C | 231.9 °C boiling point | 114 °C | -34 °C | 2602 °C density | 2.226 g/cm^3 | 0.003214 g/cm^3 (at 0 °C) | 7.31 g/cm^3 solubility in water | soluble | | insoluble dynamic viscosity | 5.8×10^-4 Pa s (at 60 °C) | | 0.001 Pa s (at 600 °C) odor | | | odorless