Input interpretation
![diamminedinitritoplatinum(II) | molar mass](../image_source/db1b00bb668c6a00f9e77bd71faf1714.png)
diamminedinitritoplatinum(II) | molar mass
Result
![Find the molar mass, M, for diamminedinitritoplatinum(II): M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: Pt(NH_3)_2(NO_2)_2 Use the chemical formula, Pt(NH_3)_2(NO_2)_2, to count the number of atoms, N_i, for each element: | N_i H (hydrogen) | 6 N (nitrogen) | 4 O (oxygen) | 4 Pt (platinum) | 1 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) H (hydrogen) | 6 | 1.008 N (nitrogen) | 4 | 14.007 O (oxygen) | 4 | 15.999 Pt (platinum) | 1 | 195.084 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) H (hydrogen) | 6 | 1.008 | 6 × 1.008 = 6.048 N (nitrogen) | 4 | 14.007 | 4 × 14.007 = 56.028 O (oxygen) | 4 | 15.999 | 4 × 15.999 = 63.996 Pt (platinum) | 1 | 195.084 | 1 × 195.084 = 195.084 M = 6.048 g/mol + 56.028 g/mol + 63.996 g/mol + 195.084 g/mol = 321.156 g/mol](../image_source/fa64f9e0c741911e5ba79d15734189a5.png)
Find the molar mass, M, for diamminedinitritoplatinum(II): M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: Pt(NH_3)_2(NO_2)_2 Use the chemical formula, Pt(NH_3)_2(NO_2)_2, to count the number of atoms, N_i, for each element: | N_i H (hydrogen) | 6 N (nitrogen) | 4 O (oxygen) | 4 Pt (platinum) | 1 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) H (hydrogen) | 6 | 1.008 N (nitrogen) | 4 | 14.007 O (oxygen) | 4 | 15.999 Pt (platinum) | 1 | 195.084 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) H (hydrogen) | 6 | 1.008 | 6 × 1.008 = 6.048 N (nitrogen) | 4 | 14.007 | 4 × 14.007 = 56.028 O (oxygen) | 4 | 15.999 | 4 × 15.999 = 63.996 Pt (platinum) | 1 | 195.084 | 1 × 195.084 = 195.084 M = 6.048 g/mol + 56.028 g/mol + 63.996 g/mol + 195.084 g/mol = 321.156 g/mol
Unit conversion
![0.32116 kg/mol (kilograms per mole)](../image_source/03b5d19843969432695cafc6511e945c.png)
0.32116 kg/mol (kilograms per mole)
Comparisons
![≈ 0.45 × molar mass of fullerene ( ≈ 721 g/mol )](../image_source/aabb804a85f988907f8bebf663dd6937.png)
≈ 0.45 × molar mass of fullerene ( ≈ 721 g/mol )
![≈ 1.7 × molar mass of caffeine ( ≈ 194 g/mol )](../image_source/ab3d4b581d6e5c3b5bb841527348171a.png)
≈ 1.7 × molar mass of caffeine ( ≈ 194 g/mol )
![≈ 5.5 × molar mass of sodium chloride ( ≈ 58 g/mol )](../image_source/b4eb1aa4f86a32d0ea0037609b8841fa.png)
≈ 5.5 × molar mass of sodium chloride ( ≈ 58 g/mol )
Corresponding quantities
![Mass of a molecule m from m = M/N_A: | 5.3×10^-22 grams | 5.3×10^-25 kg (kilograms) | 321 u (unified atomic mass units) | 321 Da (daltons)](../image_source/3a222871bf9d91cc39ff7b711b245e4a.png)
Mass of a molecule m from m = M/N_A: | 5.3×10^-22 grams | 5.3×10^-25 kg (kilograms) | 321 u (unified atomic mass units) | 321 Da (daltons)
![Relative molecular mass M_r from M_r = M_u/M: | 321](../image_source/077d9d0956519160b39e86263063bb33.png)
Relative molecular mass M_r from M_r = M_u/M: | 321