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wave propagation in strings

Input interpretation

wave propagation in strings
wave propagation in strings

Equation

v = sqrt(T/μ) |  v | wave propagation speed T | string tension μ | linear mass density
v = sqrt(T/μ) | v | wave propagation speed T | string tension μ | linear mass density

Input values

string tension | 1000 N (newtons) linear mass density | 100 g/m (grams per meter)
string tension | 1000 N (newtons) linear mass density | 100 g/m (grams per meter)

Results

wave propagation speed | 100 m/s (meters per second) = 223.7 mph (miles per hour) = 328.1 ft/s (feet per second) = 360 km/h (kilometers per hour) = 8640 km/day (kilometers per day)
wave propagation speed | 100 m/s (meters per second) = 223.7 mph (miles per hour) = 328.1 ft/s (feet per second) = 360 km/h (kilometers per hour) = 8640 km/day (kilometers per day)

Possible intermediate steps

Calculate the wave propagation speed using the following information: known variables | |  T | string tension | 1000 N μ | linear mass density | 100 g/m Convert known variables into appropriate units using the following: 1 N = 1000 g m/s^2: known variables | |  T | string tension | 1×10^6 g m/s^2 μ | linear mass density | 100 g/m The relevant equation that relates wave propagation speed (v), string tension (T), and linear mass density (μ) is: v = sqrt(T/μ) Substitute known variables into the equation: known variables | |  T | string tension | 1×10^6 g m/s^2 μ | linear mass density | 100 g/m | : v = sqrt((1×10^6 g m/s^2)/(100 g/m)) Separate the numerical part, sqrt((1×10^6)/100), from the unit part, sqrt((g m/s^2)/(g/m)) = m/s: v = sqrt((1×10^6)/100) m/s Evaluate sqrt((1×10^6)/100): Answer: |   | v = 100 m/s
Calculate the wave propagation speed using the following information: known variables | | T | string tension | 1000 N μ | linear mass density | 100 g/m Convert known variables into appropriate units using the following: 1 N = 1000 g m/s^2: known variables | | T | string tension | 1×10^6 g m/s^2 μ | linear mass density | 100 g/m The relevant equation that relates wave propagation speed (v), string tension (T), and linear mass density (μ) is: v = sqrt(T/μ) Substitute known variables into the equation: known variables | | T | string tension | 1×10^6 g m/s^2 μ | linear mass density | 100 g/m | : v = sqrt((1×10^6 g m/s^2)/(100 g/m)) Separate the numerical part, sqrt((1×10^6)/100), from the unit part, sqrt((g m/s^2)/(g/m)) = m/s: v = sqrt((1×10^6)/100) m/s Evaluate sqrt((1×10^6)/100): Answer: | | v = 100 m/s