Input interpretation
![Cl_2 chlorine + Al aluminum ⟶ Al2Cl3](../image_source/f8588f3176a30572acb813038abcb861.png)
Cl_2 chlorine + Al aluminum ⟶ Al2Cl3
Balanced equation
![Balance the chemical equation algebraically: Cl_2 + Al ⟶ Al2Cl3 Add stoichiometric coefficients, c_i, to the reactants and products: c_1 Cl_2 + c_2 Al ⟶ c_3 Al2Cl3 Set the number of atoms in the reactants equal to the number of atoms in the products for Cl and Al: Cl: | 2 c_1 = 3 c_3 Al: | c_2 = 2 c_3 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_3 = 1 and solve the system of equations for the remaining coefficients: c_1 = 3/2 c_2 = 2 c_3 = 1 Multiply by the least common denominator, 2, to eliminate fractional coefficients: c_1 = 3 c_2 = 4 c_3 = 2 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | 3 Cl_2 + 4 Al ⟶ 2 Al2Cl3](../image_source/36058b08f53ed845a07cec376d175f30.png)
Balance the chemical equation algebraically: Cl_2 + Al ⟶ Al2Cl3 Add stoichiometric coefficients, c_i, to the reactants and products: c_1 Cl_2 + c_2 Al ⟶ c_3 Al2Cl3 Set the number of atoms in the reactants equal to the number of atoms in the products for Cl and Al: Cl: | 2 c_1 = 3 c_3 Al: | c_2 = 2 c_3 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_3 = 1 and solve the system of equations for the remaining coefficients: c_1 = 3/2 c_2 = 2 c_3 = 1 Multiply by the least common denominator, 2, to eliminate fractional coefficients: c_1 = 3 c_2 = 4 c_3 = 2 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | 3 Cl_2 + 4 Al ⟶ 2 Al2Cl3
Structures
![+ ⟶ Al2Cl3](../image_source/c771d2690e937da55588a7fb20263e20.png)
+ ⟶ Al2Cl3
Names
![chlorine + aluminum ⟶ Al2Cl3](../image_source/2efee40072739fdfb5c71dcc5bbf2444.png)
chlorine + aluminum ⟶ Al2Cl3
Equilibrium constant
![Construct the equilibrium constant, K, expression for: Cl_2 + Al ⟶ Al2Cl3 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the activity expression for each chemical species. • Use the activity expressions to build the equilibrium constant expression. Write the balanced chemical equation: 3 Cl_2 + 4 Al ⟶ 2 Al2Cl3 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i Cl_2 | 3 | -3 Al | 4 | -4 Al2Cl3 | 2 | 2 Assemble the activity expressions accounting for the state of matter and ν_i: chemical species | c_i | ν_i | activity expression Cl_2 | 3 | -3 | ([Cl2])^(-3) Al | 4 | -4 | ([Al])^(-4) Al2Cl3 | 2 | 2 | ([Al2Cl3])^2 The equilibrium constant symbol in the concentration basis is: K_c Mulitply the activity expressions to arrive at the K_c expression: Answer: | | K_c = ([Cl2])^(-3) ([Al])^(-4) ([Al2Cl3])^2 = ([Al2Cl3])^2/(([Cl2])^3 ([Al])^4)](../image_source/06f25ab79ce659536b16a1d7790654d6.png)
Construct the equilibrium constant, K, expression for: Cl_2 + Al ⟶ Al2Cl3 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the activity expression for each chemical species. • Use the activity expressions to build the equilibrium constant expression. Write the balanced chemical equation: 3 Cl_2 + 4 Al ⟶ 2 Al2Cl3 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i Cl_2 | 3 | -3 Al | 4 | -4 Al2Cl3 | 2 | 2 Assemble the activity expressions accounting for the state of matter and ν_i: chemical species | c_i | ν_i | activity expression Cl_2 | 3 | -3 | ([Cl2])^(-3) Al | 4 | -4 | ([Al])^(-4) Al2Cl3 | 2 | 2 | ([Al2Cl3])^2 The equilibrium constant symbol in the concentration basis is: K_c Mulitply the activity expressions to arrive at the K_c expression: Answer: | | K_c = ([Cl2])^(-3) ([Al])^(-4) ([Al2Cl3])^2 = ([Al2Cl3])^2/(([Cl2])^3 ([Al])^4)
Rate of reaction
![Construct the rate of reaction expression for: Cl_2 + Al ⟶ Al2Cl3 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the rate term for each chemical species. • Write the rate of reaction expression. Write the balanced chemical equation: 3 Cl_2 + 4 Al ⟶ 2 Al2Cl3 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i Cl_2 | 3 | -3 Al | 4 | -4 Al2Cl3 | 2 | 2 The rate term for each chemical species, B_i, is 1/ν_i(Δ[B_i])/(Δt) where [B_i] is the amount concentration and t is time: chemical species | c_i | ν_i | rate term Cl_2 | 3 | -3 | -1/3 (Δ[Cl2])/(Δt) Al | 4 | -4 | -1/4 (Δ[Al])/(Δt) Al2Cl3 | 2 | 2 | 1/2 (Δ[Al2Cl3])/(Δt) (for infinitesimal rate of change, replace Δ with d) Set the rate terms equal to each other to arrive at the rate expression: Answer: | | rate = -1/3 (Δ[Cl2])/(Δt) = -1/4 (Δ[Al])/(Δt) = 1/2 (Δ[Al2Cl3])/(Δt) (assuming constant volume and no accumulation of intermediates or side products)](../image_source/fd1120a8d4f7016eff594e06a4f02159.png)
Construct the rate of reaction expression for: Cl_2 + Al ⟶ Al2Cl3 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the rate term for each chemical species. • Write the rate of reaction expression. Write the balanced chemical equation: 3 Cl_2 + 4 Al ⟶ 2 Al2Cl3 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i Cl_2 | 3 | -3 Al | 4 | -4 Al2Cl3 | 2 | 2 The rate term for each chemical species, B_i, is 1/ν_i(Δ[B_i])/(Δt) where [B_i] is the amount concentration and t is time: chemical species | c_i | ν_i | rate term Cl_2 | 3 | -3 | -1/3 (Δ[Cl2])/(Δt) Al | 4 | -4 | -1/4 (Δ[Al])/(Δt) Al2Cl3 | 2 | 2 | 1/2 (Δ[Al2Cl3])/(Δt) (for infinitesimal rate of change, replace Δ with d) Set the rate terms equal to each other to arrive at the rate expression: Answer: | | rate = -1/3 (Δ[Cl2])/(Δt) = -1/4 (Δ[Al])/(Δt) = 1/2 (Δ[Al2Cl3])/(Δt) (assuming constant volume and no accumulation of intermediates or side products)
Chemical names and formulas
![| chlorine | aluminum | Al2Cl3 formula | Cl_2 | Al | Al2Cl3 name | chlorine | aluminum | IUPAC name | molecular chlorine | aluminum |](../image_source/2e8f93e8561ec51cf5f560c997d6e933.png)
| chlorine | aluminum | Al2Cl3 formula | Cl_2 | Al | Al2Cl3 name | chlorine | aluminum | IUPAC name | molecular chlorine | aluminum |
Substance properties
![| chlorine | aluminum | Al2Cl3 molar mass | 70.9 g/mol | 26.9815385 g/mol | 160.3 g/mol phase | gas (at STP) | solid (at STP) | melting point | -101 °C | 660.4 °C | boiling point | -34 °C | 2460 °C | density | 0.003214 g/cm^3 (at 0 °C) | 2.7 g/cm^3 | solubility in water | | insoluble | surface tension | | 0.817 N/m | dynamic viscosity | | 1.5×10^-4 Pa s (at 760 °C) | odor | | odorless |](../image_source/c9daad5d9abc38bb18a2c8d7e7cccb94.png)
| chlorine | aluminum | Al2Cl3 molar mass | 70.9 g/mol | 26.9815385 g/mol | 160.3 g/mol phase | gas (at STP) | solid (at STP) | melting point | -101 °C | 660.4 °C | boiling point | -34 °C | 2460 °C | density | 0.003214 g/cm^3 (at 0 °C) | 2.7 g/cm^3 | solubility in water | | insoluble | surface tension | | 0.817 N/m | dynamic viscosity | | 1.5×10^-4 Pa s (at 760 °C) | odor | | odorless |
Units