CaO + P2O5 = Ca3(PO4)2

lime + P2O5 ⟶ tricalcium diphosphate

Balance the chemical equation algebraically: + P2O5 ⟶ Add stoichiometric coefficients, c_i, to the reactants and products: c_1 + c_2 P2O5 ⟶ c_3 Set the number of atoms in the reactants equal to the number of atoms in the products for Ca, O and P: Ca: | c_1 = 3 c_3 O: | c_1 + 5 c_2 = 8 c_3 P: | 2 c_2 = 2 c_3 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_2 = 1 and solve the system of equations for the remaining coefficients: c_1 = 3 c_2 = 1 c_3 = 1 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | 3 + P2O5 ⟶

+ P2O5 ⟶

lime + P2O5 ⟶ tricalcium diphosphate

| lime | P2O5 | tricalcium diphosphate formula | | P2O5 | Hill formula | CaO | O5P2 | Ca_3O_8P_2 name | lime | | tricalcium diphosphate

| lime | P2O5 | tricalcium diphosphate molar mass | 56.077 g/mol | 141.94 g/mol | 310.17 g/mol phase | solid (at STP) | | melting point | 2580 °C | | boiling point | 2850 °C | | density | 3.3 g/cm^3 | | 3.14 g/cm^3 solubility in water | reacts | |